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Gemiola [76]
3 years ago
6

You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the di

stance d from the tee to the hole.
Mathematics
2 answers:
artcher [175]3 years ago
7 0

Answer:

90=3/4 + d

Explanation :

Where:

90 represents the yard

3/4 represents distance travelled by ball

d represents distance from tee to the hole.

Hence:

90=3/4 + d

frutty [35]3 years ago
7 0

Answer:

Step-by-step explanation:

Given:

Distance travelled, D = 90 yards

Distance from the tee to the hole = x

Ratio of the distance from the tee to the hole = 3/4

3/4 × x = 90

x = 90 × 4/3

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write the following integers in ascending order (smallest to biggest).1._5,2,1,_8 2. _4,_3,_5,2 3._10,_15,-7​
Bond [772]

Answer:

1.1,2,5,8

2.2,3,4,5

3.-7,10,15

Step-by-step explanation:

hope help

7 0
3 years ago
Calendario matematico la necesito ya porfa.
Murrr4er [49]

The common difference based on the sequence given is 15.

<h3>How to illustrate the sequence?</h3>

It should be noted that the sequence given Isa arithmetic sequence.

The common difference will be the second term minus the first term. This will be:

= 101 - 86

= 15

In conclusion, the difference is 15.

Learn more about sequence on:

brainly.com/question/6561461

#SPJ1

8 0
2 years ago
the performing arts department put in its spring show on Friday and Saturday nights. the price of a ticket was the same both nig
Galina-37 [17]
Let p= the price of a ticket
Let c= the cost to put on the show

Formula:
(profit) = (ticket price) * (number of people) - (cost to put on show)
We have two equations here:
500=120p-c
400=100p-c
Solve:
100=20p
⇒p=5
⇒400=100(5)-c
⇒400=500-c
⇒c=100

So the price of a ticket is $5, and the cost to put on the show is $100.
3 0
3 years ago
A car traveled 300 miles on 15 gallons of gas. How many miles does the car travel on 1 gallon of gas?​
katrin [286]

Answer:

20 miles for 1 gallon.

Step-by-step explanation:

20 x 15 = 300

4 0
2 years ago
Read 2 more answers
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
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