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Gemiola [76]
3 years ago
6

You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the di

stance d from the tee to the hole.
Mathematics
2 answers:
artcher [175]3 years ago
7 0

Answer:

90=3/4 + d

Explanation :

Where:

90 represents the yard

3/4 represents distance travelled by ball

d represents distance from tee to the hole.

Hence:

90=3/4 + d

frutty [35]3 years ago
7 0

Answer:

Step-by-step explanation:

Given:

Distance travelled, D = 90 yards

Distance from the tee to the hole = x

Ratio of the distance from the tee to the hole = 3/4

3/4 × x = 90

x = 90 × 4/3

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MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
3 years ago
7. Is it proportional?
SCORPION-xisa [38]

Answer:

A unit rate is the rate of change in a relationship where the rate is per 1.

The rate of change is the ratio between the x and y (or input and output) values in a relationship.  Another term for the rate of change for proportional relationships is the constant of proportionality.

If the rate of change is yx, then so is the constant of proportionality.  To simplify things, we set  yx=k, where k represents the constant of proportionality.  

If you solve a yx=k equation for y, (like this: y=kx), it is called a direct variation equation. In a direct variation equation, y varies directly with x. When x increases or decreases, y also increases or decreases by the same proportion.

To find y in a direct variation equation, multiply x by the constant of proportionality, k.

For example: Given the relationship y=7x, the constant of proportionality k=7,  so if x=3,  then y=3×7 or 21.

Given the same relationship, if x=7,  then y=7×7, or 49.  

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
47,258 redondear el decimal hasta la centésima más próxima ​
KIM [24]

Answer:

I don't speak Spanish

Step-by-step explanation:

4 0
2 years ago
Help pls , graph and linear equations
drek231 [11]

Answer:

4- -1=3

Step-by-step explanation:

7. m=3 (4,-1)

do the () inside first so

4- -1 = 3

hope this helps for number 7

5 0
2 years ago
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
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