I'll assume the usual definition of set difference,
.
Let
. Then
and
. If
, then
and
. This means
and
, so it follows that
. Hence
.
Now let
. Then
and
. By definition of set difference,
and
. Since
, we have
, and so
. Hence
.
The two sets are subsets of one another, so they must be equal.
The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices
.
Proof of one direction for example:
Let
. Then
and
, which in turn means
for all
. This means
, and
, and so on, where
, for all
. This means
, and
, and so on, so
. Hence
.
Answer:
A unit rate is the rate of change in a relationship where the rate is per 1.
The rate of change is the ratio between the x and y (or input and output) values in a relationship. Another term for the rate of change for proportional relationships is the constant of proportionality.
If the rate of change is yx, then so is the constant of proportionality. To simplify things, we set yx=k, where k represents the constant of proportionality.
If you solve a yx=k equation for y, (like this: y=kx), it is called a direct variation equation. In a direct variation equation, y varies directly with x. When x increases or decreases, y also increases or decreases by the same proportion.
To find y in a direct variation equation, multiply x by the constant of proportionality, k.
For example: Given the relationship y=7x, the constant of proportionality k=7, so if x=3, then y=3×7 or 21.
Given the same relationship, if x=7, then y=7×7, or 49.
Step-by-step explanation:
Answer:
I don't speak Spanish
Step-by-step explanation:
Answer:
4- -1=3
Step-by-step explanation:
7. m=3 (4,-1)
do the () inside first so
4- -1 = 3
hope this helps for number 7
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer