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Hoochie [10]
3 years ago
5

How is this ejercice: 15+x=4

Mathematics
1 answer:
alexandr402 [8]3 years ago
4 0
X equals negative 11
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PLEASE HELP ASAP ILL GIVE 11 points
ser-zykov [4K]

Answer:

11

Step-by-step explanation:

6^2 = 6 x 6 = 36

5^2 = 5 x 5 = 25

36 - 25 = 11

7 0
3 years ago
Read 2 more answers
List all the elements of the following set. Use set notation and the listing method to describe the set. The set of all counting
Tatiana [17]

Answer:

different question

Step-by-step explanation:

question is wrong

3 0
3 years ago
Christia is saving for a new tablet. It costs $90. She has already saved $23. How much more does she need to save?
Vilka [71]

Answer:

67

Step-by-step explanation:

subtract 90 from 23 and you should have what you need to save.

8 0
3 years ago
If f(x) = 4x + 2, what is the value of f(3)? <br><br> O 8<br> O 14<br> O 45<br> O 66
lutik1710 [3]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
The functions f(x) = −(x − 1)2 5 and g(x) = (x 2)2 − 3 have been rewritten using the completing-the-square method. apply your kn
ale4655 [162]

The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.

<h3>How to determine the vertex for each function is a minimum or a maximum? </h3>

Given:

$\mathrm{f}(\mathrm{x})=-(\mathrm{x}-1)^{2}+5$ and

$\mathrm{g}(\mathrm{x})=(\mathrm{x}-2)^{2}-3$

The generalized equation of a parabola in the vertex form exists

$y=a(x-h)^{2}+k

Vertex of the function f(x) exists (1, 5).

Vertex of the function g(x) exists (-2, -3).

Now, if (a > 0) then the vertex of the function exists minimum, and if (a < 0) then the vertex of the function exists maximum.

The vertex of the function f(x) exists at a maximum and the vertex of the function g(x) exists at a minimum.

To learn more about the vertex of the function refer to:

brainly.com/question/11325676

#SPJ4

8 0
2 years ago
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