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jeka57 [31]
3 years ago
10

There are 100 pennies in a dollar.What fraction of a dollar is 61 pennies?Write it as a fraction,as a decimal,and in word from.

Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

61/100, 61%, 0.61, sixty-one percent, sixty-one one hundredths

Step-by-step explanation:

61/100

61%

0.61

sixty-one percent

sixty-one one hundredths

You might be interested in
Substitute x+2y=8 3x+2y=6
vekshin1
Use x+2y=8
Subtract 2y to make
x=8-2y

Plug this in to the other equation
3(8-2y)+2y=6

Distribute the 3
24-6y+2y=6

Combine like terms
24-4y=6

Solve
18/4=y, 9/2=y

Plug and solve for x
X+2y=8
X+(2*9/2)=8
X+9=8
X=-1
8 0
3 years ago
Read 2 more answers
I need to pass this but I just need help on the percentage
Tcecarenko [31]

Answer:

38%

Step-by-step explanation:

$600 is 100%

$60 is 10%

$6 is 1%

3 60s go into 228 with 48 still left.

6 times 8 is 48.

So its 38%.

6 0
3 years ago
Which statement best describes how to determine whether f(x) = x4 – x3 is an even function?
Setler79 [48]
It would equal x=0 so no
3 0
4 years ago
Simplified, -14xy − (-3xy) is
Debora [2.8K]

Answer:

-11xy

Step-by-step explanation:

-14xy -(-3xy)

multiply the bract first - sign * minus sign is plus sign

-14xy+3xy

since they are like terms u can subtract them.u should subtract them because minus and plus means subtract and we should put minus sign in front of the answer because 14 is the highest number and it's sign is negative .

-11xy

5 0
3 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
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