H(t)=-16t^2+96x+256. what is the initial value?
1 answer:
Answer:
256
Step-by-step explanation:
The intial value should be where it started which in this case would be when
t = 0
So if you make t = 0
h(0) = 16(0)^2+96(0)+256
h(0)= 256
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