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Ksenya-84 [330]
3 years ago
13

H(t)=-16t^2+96x+256. what is the initial value?

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

256

Step-by-step explanation:

The intial value should be where it started which in this case would be when

t = 0

So if you make t = 0

h(0) = 16(0)^2+96(0)+256

h(0)= 256

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Answer:

x = 5

Step-by-step explanation:

20(20-x)=300

1. Divide both sides by 20.

20(20-x)/20 = 300/20

2. Simplify.

20-x=15

3. Subtract 20 from both sides.

20-x-29=15-20

4. Simplify.

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5. Divide both sides by -1.

-x/-1 = -5/-1

6. Simplify.

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Step-by-step explanation:

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