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Ksenya-84 [330]
3 years ago
13

H(t)=-16t^2+96x+256. what is the initial value?

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

256

Step-by-step explanation:

The intial value should be where it started which in this case would be when

t = 0

So if you make t = 0

h(0) = 16(0)^2+96(0)+256

h(0)= 256

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Answer:

Your <u>correct</u> answer is 14t - 40

Step-by-step explanation:

Combine like terms:

10t + 3t + t = 14t

Since there are no other integers, just tag on the -40:

14t - 40

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95(.35)= 33.25
95-33.25=61.75$ discounted price
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Solve each system by the addition method.
Aneli [31]
-4x + 7y = 9  ⇒ -4x + 7y = 9  ⇒     8x - 14y = -18
2y = -5x - 22 ⇒ -5x - 2y = 22 ⇒ <u>-35x - 14y = 154</u>
                                                               <u>43x</u> = <u>-172</u>
                                                                43       43
                                                                   x = -4
                                                        -4x + 7y = 9
                                                     -4(-4) + 7y = 9
                                                          16 + 7y = 9
                                                        <u>- 16        - 16</u>
                                                                  <u>7y</u> = <u>-7</u>
                                                                   7      7
                                                                    y = -1
                                                              (x, y) = (-4, -1)
7 0
2 years ago
I need help on iready
kicyunya [14]

Answer:

the answer is 3

Step-by-step explanation:

because if you do the methoes method you know that it rules out 1 and 2 after you do that its just between 3 and 4, for the caunususicon there has to be one, that is why i think its 3. hope this helps!

7 0
3 years ago
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