4 years ago

H(t)=-16t^2+96x+256. what is the initial value?

Mathematics

1 answer:

Eduardwww [97]4 years ago

5 0

Answer:

256

Step-by-step explanation:

The intial value should be where it started which in this case would be when

t = 0

So if you make t = 0

h(0) = 16(0)^2+96(0)+256

h(0)= 256

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