Which of the following is a productivity strategy for collaboration?
-
A. Saving focused work for a time of day when you feel most creative.
- B. Employing the 80/20 rule to prioritize tasks.
- C. Posting files to a web-based shared site.
- D. Using white noise to block distractions in the office.
<u>Answer:</u>
Posting files to a web-based shared site is a productivity strategy for collaboration.
- C. Posting files to a web-based shared site.
<u>Explanation:</u>
Collaborative software or groupware is application programming intended to help individuals taking a shot at a typical errand to achieve their objectives. This permits individual to impart thoughts and their abilities to different individuals with the goal that the assignment can be done both proficiently and adequately.
Joint effort stages ordinarily incorporate an email customer, Web conferencing, internet based life sharing, video capacities, report sharing abilities, texting and that's just the beginning. Endeavor joint effort stages are intended to be introduced on-premises or conveyed by means of the Web as cloud-based administrations.
On modern network cards, this should just work.
It is advisable to give each laptop its own fixed IP address, such as 192.168.1.1 and 192.168.1.2 (with a netmask of 255.255.255.0)
However, you need to define what you expect to work. The first thing to try is ping <em>the other</em> machine from the command prompt, e.g.:
C:\> ping 192.168.1.2
Then, you can try to access shared network drives if you have enabled that. In the file explorer, try typing: \\192.168.1.2
He is a victim of plagiarism.
Plagiarism is when someone steals someone else's work, to help benefit themselves. Taking credit for the other person work.
Hope this helps!
Answer:
if ( name1 > name2) {
first = name1;
} else {
first = name2;
}
Explanation:
First you need take a decision for that reason you need and if - else structure to decide if asign the variable name1 or the variable name2 to the result. Later you can use an > or < to compare two strings because it use the ASCII code to compare wich one is larger than another.
if ( name1 > name2) {
first = name1;
} else {
first = name2;
}
