Since both coefficients next to your <em>y</em><em>'</em>s are identical use the EliminationMethod by multiplying one of the equations by -1 to form <em>additive </em><em>inverses</em><em>,</em><em> </em>meaning they result in 0:
-1[{2x - 3y = 16}]↷
{5x - 3y = 13}
{-2x +<em> </em>3y = -16
{5x - 3y= 13
----------------
3x = -3 [Divide by 3]
x = -1
y = -6 [plug in "-1" back into both equations to confirm their authenticities]
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Y=-2 is a horizontal line, each point which lies on this line has the y-coordinate -2. Only in option C both points have the y-coordinate equal to -2. The answer is C.
