All categories

4 years ago

If a 90 degree angle is a right angle, how does 360 degrees make a circle? Not for school,just for thought.

Mathematics

2 answers:

kotykmax [81]4 years ago

8 0

180 is a flat line and if you turn it’s not exactly a circle it seems that way but it just rotating

Hoochie [10]4 years ago

5 0

Answer:

See below

Step-by-step explanation:

90° = 1 rt ∠ = ¼ circle

360° = 4 rt ∠ = ⁴/₄ circle = 1 circle

360° = 1 circle

You might be interested in

Please help me to solve this problem

skelet666 [1.2K]

Answer:

y = 3x -5

Explanation:

Since it's parallel, it will have the same slope: 3.

So you'll have y = 3x + a, and we need to find a.

Plug in the values for the point we are given:

7 = 3(4) + a

7 = 12 + a

a = -5

<h3>So there you have it: y = 3x - 5</h3>

7 0

3 years ago

Read 2 more answers

Different groups of 50 graduates of an engineering school were asked the starting annual salary for their first engineering job

Romashka-Z-Leto [24]

D. $64,000
I hope this answer helped you.

7 0

3 years ago

After remodeling the circular deck, the Museum Board Members decided to also build a

UNO [17]

9514 1404 393

Answer:

3929 square feet

Step-by-step explanation:

The radius of the fence circle is half its diameter, so is 51.4 feet. The area of a circle is given by the formula ...

A = πr^2

The difference in areas of the two regions is found by subtracting the smaller area from the larger one. So, the difference in area between the fenced area of radius 51.4 feet and the playground area of radius 37.3 feet is ...

∆A = π(51.4^2 -37.3^2) = 1250.67π ≈ 3929 . . . square feet

8 0

3 years ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

5 0

4 years ago

The sum of two intergers is 74. The larger is 26 more than twice the smaller. Find the two integers

GalinKa [24]

x - smaller integer

$x+x+26=74\\ 2x=48\\ x=24\\\\ x+26=24+26=50$

24 and 50

8 0

3 years ago