Answer:
Notifying the errors is always useful .
Explanation:
The errors should always be notified to the developer. It is useful and is important. When we provide notifications on the screen, it helps the user and it can be used to provide feedback. In regard to developmental work, it has to be important and confidential and we use the help of email to inform or notify errors to the organization. This will help the company from negative criticism and helps the company perform better. We can also write an error log when we face the same error again and again even after notifying the developer organization. This helps to put a reminder to the organization that immediate check has to be dome and eliminate the error from the source.
Some disadvantages are if we do not keep timer implementation, the alert keeps on popping on the screen, which is irritable.
SUWIDHA stands for Single User-friendly Window Disposal & Help-line for Applicants.
Hope it helps
Answer:
^[A-Fa-f0-9]+$
Explanation:
The hexadecimal (Base 16) can contain 0-9, A-F, a-f and any of these can be the part of the Hexadecimal base 16 code.
In python we have the re.match function, and the syntax is as below:
re.match(pattern, string, flag=0). And we can use this function to check whether the entered char variable is a regex or not. Like:
re.match(pattern,x, flag=0)
Answer & Explanation:
To print 10 on a line and each number separated by space; you make the following modifications.
print(str(i)+" ",end=' ')
str(i)-> represents the actual number to be printed
" "-> puts a space after the number is printed
end = ' ' -> allows printing to continue on the same line
if(count == 10):
print(' ')
The above line checks if count variable is 10;
If yes, a blank is printed which allows printing to start on a new line;
The modified code is as follows (Also, see attachment for proper indentation)
count = 0
for i in range(100,201):
if(i%6 == 0 and i%5!=0) or (i%5 ==0 and i%6!=0):
print(str(i)+" ",end=' ')
count = count + 1
if(count == 10):
print(' ')
count = 0
In our bag, 1/2 is peanuts, 1/4 is chocolate and 1/4 is dried fruit.
The likelihood of drawing a chocolate therefore is 1/4.
The likelihood of drawing a peanut is 1/2 and the likelihood of drawing a dried fruit is 1/4.
Thus, D is the correct answer because the 1/4 likelihood of drawing a chocolate is less than the 1/2 chance of drawing a peanut.
