If you break the fraction into floating decimal then we can figure out all the values from largest to smallest or either.
a) 0.0271
b) 1/4 = 0.25
c) 0.29
d) 23% = 0.23
e) 1/5 = 0.2
From above numbers, we can organise them from largest to smallest...
c, b, d, e, a (Answer)
-3 im am sure its correct
Answer:
See below.
Step-by-step explanation:
So we have the parent function:
![f(x)=x^2](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2)
And it was transformed into:
![g(x)=(3x)^2+6](https://tex.z-dn.net/?f=g%28x%29%3D%283x%29%5E2%2B6)
First, the +6 at the very end simply tells us that the graph was shifted upwards by 6 units.
For the (3x), this is essentially saying that:
![f(x)=x^2](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2)
If we use 3x for x:
![f(3x)=(3x)^2](https://tex.z-dn.net/?f=f%283x%29%3D%283x%29%5E2)
Therefore, we essentially multiplied the x variable by 3.
In other words, this is a horizontal compression by a factor of 3.
So, our transformations are:
1) 6 units upwards
2) Horizontal compression by 3
Use this formula
![log_{5}(10x + 5) - log_{5}(x - 7) = \\ log_{5}( \frac{10x + 5}{x - 7} )](https://tex.z-dn.net/?f=%20%20log_%7B5%7D%2810x%20%2B%205%29%20%20-%20%20log_%7B5%7D%28x%20-%207%29%20%20%3D%20%20%5C%5C%20%20log_%7B5%7D%28%20%5Cfrac%7B10x%20%2B%205%7D%7Bx%20-%207%7D%20%29%20)
after thet you have
![log_{5}( \frac{10x + 5}{x - 7} ) = 2](https://tex.z-dn.net/?f=%20log_%7B5%7D%28%20%5Cfrac%7B10x%20%2B%205%7D%7Bx%20-%207%7D%20%29%20%20%3D%202)
open this up
![\frac{10x + 5}{x - 7} = {5}^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B10x%20%2B%205%7D%7Bx%20-%207%7D%20%20%3D%20%20%7B5%7D%5E%7B2%7D%20)
and from now you sould be fine!
The answer to your question is 10. You’re welcome.