Given:
In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.
To find:
The measure of angle P.
Solution:
According to the Law of Cosines:
Using Law of Cosines in triangle OPQ, we get
On further simplification, we get
Therefore, the measure of angle P is 79 degrees.
I will tell you use a calculator and leave the answer there. Try the math see if you get it correct. If you don't tell me!
Answer:
3
Step-by-step explanation:
Triangles with the same shape but different size are proportional. Proportional means that their side lengths form equal ratios. To solve for x, set up a proportion.
The ratios we will create will be 
where each long and short are corresponding sides from each triangle.
So write:
To solve, cross multiply numerator with denominator.
4(2.25) = 3(x)
9 = 3x
3 =x
Answer:
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Step-by-step explanation:
5z^2−9z=−7z−5
We need to get all the terms on one side (set the right side equal to zero)
Add 7z to each side
5z^2−9z+7z=−7z+7z−5
5z^2−2z=−5
Add 5 to each side
5z^2−2z+5=−5 +5
5z^2−2z+5=0
This is in the form
az^2 +bz+c = 0 so we can use the quadratic formula
where a = 5 b = -2 and c = 5
-b± sqrt(b^2-4ac)
-------------------------
2a
-(-2)± sqrt((-2)^2-4(5)5)
-------------------------
2(5)
2± sqrt(4-100)
-------------------------
10
2± sqrt(-96)
-------------------------
10
2± sqrt(16)sqrt(-1) sqrt(6)
-------------------------
10
2± 4i sqrt(6)
-------------------------
10
1/5 ± 2/5 i sqrt(6)
Splitting the ±
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
<span>1 7/8 x 2 1/3
= 15/8 x 7/3
= 35/8
= 4 3/8
hope it helps</span>
