Answer:
<u>Option 2</u>
Step-by-step explanation:
Evaluating the options :
<u>Option 1</u>
- 2 |x - 5| - 4 < -8
- 2 |x - 5| < -4
- |x - 5| < -2
- Empty set as modulus cannot be less than 0
<u>Option 2</u>
- |2x - 1| - 7 < -6
- |2x - 1| < 1
- x < 1
- There is a solution set other than empty set
<u>Option 2</u> is the right answer.
First, we find the area of the circle.
A = pi * r^2
A = pi * (1 cm)^2
A = pi cm^2
The area of the circle is pi cm^2.
The area of the triangle is also pi cm^2.
Now we use the area of a triangle.
A = (1/2)bh
(1/2)bh = A
(1/2)(3 cm)h = pi cm^2
(3 cm)h = 2pi cm^2
h = (2/3)pi cm
The exact height is ![\dfrac{2\pi}{3} ~cm](https://tex.z-dn.net/?f=%20%5Cdfrac%7B2%5Cpi%7D%7B3%7D%20~cm%20)
If you want an approximate height, then it is 2.09 cm.
36/-9-5=14/7-11
36/-9=-4
-4-5=-9
14/7=2
2-11=-9
The answer is A. W=1+5t w=3+5.5t