What is the product of 2.5x10*-15 and 3.9x10*26?
2 answers:
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Answer:
The required point is, (7, -2)
Step-by-step explanation:
The straight line passing through (0,0) and (2,7) is,
y =
⇒ y = 3.5x --------------(1)
Now, the straight line perpendicular to this line and passing through (0, 0) is
y =
⇒ 7y + 2x = 0 -------------(2)
Let, (h,k) be the required point.
then, it is on the line 7y + 2x = 0
⇒7k + 2h = 0
⇒k = ------------(3)
Again, distance from (0,0) of (h, k) is same as that of (2,7)
⇒
⇒ = 53 [putting the value of k from (3)]
⇒ = 49
⇒h = 7 [since, (h,k) is in 4th quadrant, so,h >0]
So, k = -2 [putting the value of h in (3)]
So, the required point is, (7, -2)
Answer:
Remainder when p(x) is divided by (x+2) is -29
Step-by-step explanation:
p(x) =
When p(x) is divided by (x-2), remainder is 19.
p(x - 2 = 0) gives the remainder when p(x) is divided by (x-2)
x - 2 = 0
x = 2
p(x-2=0) = p(2) = = 19
8 - 8 + 16 + k = 19
k = 3
p(x) =
p(x + 2 = 0) gives the remainder when p(x) is divided by (x+2)
x + 2 = 0
x = -2
p(x+2=0) = p(-2) =
p(-2) = - 8 - 8 - 16 + 3 = -29
Remainder when p(x) is divided by (x+2) is -29