The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.
Answer:
Step-by-step explanation:
i² = -1
-8(-1) + 3 = 8 + 3 = 11
Answer:
1: AAS, RQC 2: ASA, SRP
Step-by-step explanation:
(1) We are shown that two angles and one side are congruent in the order of AAS. Make sure you write the letters in terms of the corresponding angles. The angles and sides are congruent because the problem labels it for us. For example, B,A,C=R,Q,S. Answers: AAS, RQC.
(2) We are shown that two angles and one side are congruent in the order of ASA. Make sure you write the letters in terms of the corresponding angles again. For example, P,Q,R=P,S,R. The angles are congruent because the problem labels it for us. Side PR is congruent to side PR by reflexive property. Answers: ASA, SRP.
I hope this helped :) Good luck
Answer:
Step-by-step explanation:
![\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20h%28x%29%20%3D%205x%2B2%5C%5C%5C%5CPut%20%5C%20h%28x%29%20%3D%20-8%5C%5C%5C%5C-8%20%3D%205x%2B2%5C%5C%5C%5CSubtract%20%5C%202%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C-8-2%20%3D%205x%5C%5C%5C%5C-10%20%3D%205x%5C%5C%5C%5CDivide%5C%20both%20%5C%20sides%20%5C%20by%20%5C%205%5C%5C%5C%5C-10%20%2F%205%20%3D%20x%20%5C%5C%5C%5Cx%20%3D%20-2%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
im having the same problem,
Step-by-step explanation:
maybe search it up on google and see what comes up
