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oksano4ka [1.4K]
3 years ago
8

Unit rate for $32.05 for 15 gal

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

im having the same problem,

Step-by-step explanation:

maybe search it up on google and see what comes up

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A fruit stand has to decide what to charge for their produce. They need $5.30 for 1 apple and 1 orange. They also need $7.30 for
Aneli [31]

Answer:

A fruit stand has to decide what to charge for their produce.

They need $ 5.30 for 1 apple and 1 orange.

They also need $ 7.30 for 1 apple and 2 oranges.

TO DETERMINE

To put this information into a system of linear equations.

TO find a unique price for an apple and an orange

EVALUATION

Let the price of an apple = x and price of an orange = y

So From the first condition that they need $ 5.30 for 1 apple and 1 orange we get

\sf{x + y = 5.30}x+y=5.30 - - - - Equation 1

Again from second condition that they need $ 7.30 for 1 apple and 2 oranges we get

\sf{x + 2y = 7.30}x+2y=7.30 - - - - Equation 2

So the required Set of linear equations are

x + y = 5.30

x + 2y = 7.30

Equation (2) - Equation (1) we get

y = 2

From Equation (1) we get

x = 5.30 - 2 = 3.30

Hence price of an apple = $ 3.30

The price of an orange = $ 2

7 0
2 years ago
Read 2 more answers
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
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Which solution set is graft on the number line
vfiekz [6]

Answer:

x < 1

Step-by-step explanation:

an open circle means it contains no equal signs.....everything to the left is shaded....means it is less then

x <  1 (thats a less then sign only) ....no equal sign in there

4 0
2 years ago
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Which statement best describes the polynomial? 13y^8-4y^7+3y
Marina CMI [18]
Definitely B.  Note how the powers of y are presented in descending order by power:    y^8, y^7, y^1.

3 0
3 years ago
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Is x-y=1 a direct variation
zhenek [66]

Answer:

Xy=1/5......

Step-by-step explanation:

because

7 0
3 years ago
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