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8_murik_8 [283]
3 years ago
9

A solid cylinder and a thin-walled hollow cylinder have the same radii. They are rolling horizontally toward the bottom of an in

cline. Assuming there is no friction, what is the maximum height each one reaches (in terms of the variables involved)?
Physics
1 answer:
Wittaler [7]3 years ago
8 0

Answer:

height solid / height hollow = 3/4

Explanation:

the height reached is directly proportional to the original KE of the object.

Total KE solid

=1/2mv^2+1/2\times1/2m r^2(v^2 / r^2 )=3/4mv^2

Total KE hollow = 1/2mv^2+1/2mr^2(v^2 / r^2 )=mv^2

height solid / height hollow = 3/4

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Suppose you increase your walking speed from 6s to 12 m/s in a period of 2 s. What is acceleration
ElenaW [278]

As we know that acceleration is given as

a = \frac{v_f - v_i}{t}

here we know that

v_i = 6 m/s

v_f = 12 m/s

\Delta t = 2 s

now we will have

a = \frac{12 - 6}{2}

a = 3 m/s^2

so acceleration will be 3 m/s^2

5 0
3 years ago
An unwary football player collides with a padded goalpost while running at a velocity of 5.70 m/s and comes to a full stop after
ollegr [7]
The relationship between the initial velocity, final velociy, distance, and deceleration can be expressed in the following equation.
          
                     2(a)(0.270 m) = 0² - (5.70 m/s)²

The value of a (which is the deceleration) is 0.06 m/s². Thus, the answer is that the deceleration value is approximately 0.06 m/s².
6 0
4 years ago
A retaining wall is 5m long (into the plane of the paper), and it is supported by an anchor rod. The soil it supports has a weig
vekshin1

Knowing that the greatest horizontal pressure is the pressure made by the material on the wall -considering for that the total height of the wall-, then P = 4.375 t/m

---------------------

<u />

<u>Available data</u>:

  • The wall is 5m long into the plane   ⇒  H
  • The soil density is 1.4 metric tonnes per cubic metre  ⇒ γ
  • K = 0.25  ⇒  Coefficient of earth pressure. Depends on the angle.

From this information, we need to calculate the greatest horizontal pressure.

Horizontal pressure refers to the force made by the supported soil on the retaining wall that tends to deflect the wall outward.

We can calculate horizontal pressure at different heights from the top. And since we need to calculate the greatest horizontal pressure, we need to consider the total height that equals the wall height, H.  

To do it, we will use the following formula, and replace the terms.

P  = [ k   γ H² ] / 2

P = [ 0.25 x 1.4 t/m³ x 5m² ] / 2

P = 8.75/2

P = 4.375 t/m          

------------------------------------------

Related link: brainly.com/question/19381739?referrer=searchResults

                     brainly.com/question/12359444?referrer=searchResults

7 0
3 years ago
The instant before a tennis racquet hits a 0.057 kg tennis ball, the velocity of the ball is 55 m/s west. The instant after
Wewaii [24]

Answer: 6700m/s^2 E

Explanation:

Given the following :

Velocity of ball before being hit by a racquet = initial velocity(u) = 55m/s W

Velocity of the ball after being hit = final Velocity (v) = 45m/s E

Time of contact between ball and racquet (t) = 1.5 × 10^-2

The acceleration of a body is the change in Velocity of a body with time. It given by:

Acceleration (a) = [final Velocity(v) - initial velocity(u)] / time(t)

The westward direction is towards the left and thus Velocity takes a negative value, similarly, if it's towards the right, Velocity takes a positive value.

Therefore,

a = [45 - (-55)] / 1.5×10^-2

a = [45 + 55] / 0.015

a = 100 / 0.015

a = 6666.6666 m/s^2

a = 6700m/s^2 E

Since the value of acceleration is positive, the direction is towards the East (acceleration is in the direction of the ball's final Velocity).

5 0
3 years ago
Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
4 years ago
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