Answer:
i d k about that but I know it`s a Polish thing
Answer:
76 mi/h
Explanation:
= Velocity of car A = 50 mi/h
a = Distance car A travels = 40 mi
= Velocity of car B = 60 mi/h
b = Distance car B = 30 mi
c = Distance between A and B after 3 hours = √(a²+b²) = √(40²+90²) = 50 mi
From Pythagoras theorem
a²+b² = c²
Now, differentiating with respect to time
∴ Rate at which distance between the cars is increasing is 76 mi/h
The cars are getting farther apart at this time
Answer:
0.6 A
Explanation:
Applying,
I = E/(R'+r).................... Equation 1
Where I = curent or circuit supply, R'= equivalent external resistance, r = internal resistance.
From the question,
Given: E = 12 Volt,
IF the three resistors are connected in series, R' = (3+7+10) ohm = 20 ohm,
r = neglible.
Substitute these values into equation 1
I = 12/(20)
I = 0.6 A
Answer:
a. 0.16240664737515434 moles
b. 67.5 degrees Celcius
Explanation:
a. Use Ideal Gas Equation
PV=nRT
Where P = pressure in pascals, V=Volume in cubic meters, n=number of moles, R is a constant=8.314 J/mol.K and T is temperature in Kelvin.
27C = 273+27=300Kelvin
volume 4L = 0.004m^3
Pressure = 1atm = 101325 Pascal
PV=nRT
101325Pa*0.004m^3=n*8.314J/mol.K*300K
Solving for n from the above you get n=0.16240664737515434 moles
b.Use combined gas law equation
P1*V1/T1=P2*V2/T2
P1= 1atm
V1=4L
T1=27C
P2= 4/16 L =0.25L
P=1*40 atm = 40atm
We do not know T2
USING THE FORMULA
(1atm*4L)/27C = (40atm*0.25L)/T2
(1*4)/27=(40*0.25)/T2
IF you simplify for T2, you get 67.5
Hence final temperature = 67.5 degrees Celcius
