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3 years ago

6

Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i

s h = 0.80 m, what is the current (in A) flowing through the rectangular toroid when the energy in its magnetic field is 9.0 ✕ 10−6 J?

1 answer:

V125BC [204]3 years ago

5 0

Answer:

Current in the toroid will be $I=17.32\times 10^{-3}A$

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid $E=9\times 10^{-16}J$

We have to find the current in the toroid

Magnetic energy stored is equal to $E=\frac{1}{2}Li^2$

$9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2$

$I=17.32\times 10^{-3}A$

So current in the toroid will be $I=17.32\times 10^{-3}A$

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Explanation:

A)

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- The frictional force, $F_f$ , backward

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2)

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

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C)

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a is the acceleration

s is the distance covered

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u = 0 (it starts from rest)

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s = 350 m

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4)

For this part of the problem, we can use the following suvat equation:

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