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Makovka662 [10]
3 years ago
5

Container A contains 10.0 g of liquid isopropyl alcohol which has a latent heat of vaporization of 732 J/g. Container B contains

10.0 g of liquid ethanol which has a latent heat of vaporization of 841 J/g. Both containers are brought to their respective freezing points. Heat is then removed from both containers at the same rate. The container whose contents will freeze first is:
Chemistry
1 answer:
igomit [66]3 years ago
7 0
By definition, the <span>latent heat associated with melting a </span>solid<span> or </span>freezing<span> a </span>liquid<span> is called the </span>heat of fusion.

Container A has a <span>latent heat of vaporization of 732 J/g.
Container B has a </span><span>latent heat of vaporization of 841 J/g.

Latent heat of vaporization refers to the</span><span> vaporizing a liquid or a solid or condensing a vapour.

This means that Container A boils first because it has lower latent heat of vaporization. 

</span><span>As you heat a solid, turning it into a gas, the kinetic energy of the molecules are increased to a point where there are no forces of attraction between the molecules. Thus, Container B will freeze faster than Container A</span>
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