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3 years ago

What caused the bubbles to form when you added the catalase to the hydrogen peroxide and water mixture at 40 °c?

2 answers:

7 0

<span>What caused the bubbles to form when you added the catalyses to the hydrogen peroxide and water mixture at 40 °C? A. Catalyses activity heated the solution to its boiling point. B. Hydrogen gas formed during the formation of hydrogen peroxide. C. Oxygen gas formed during the decomposition of hydrogen peroxide.

This would be the water, mixture.</span>

Mrac [35]3 years ago

4 0

$\boxed{{\text{Formation of oxygen}}}$ caused the bubbles to form when catalase is added to the hydrogen peroxide and water mixture at $40\;^\circ {\text{C}}$ .

Further explanation:

Catalyst:

These are the substances that change the rate of a chemical reaction but these don’t get consumed in the reaction. These have wide applications in petroleum, fertilizer and pharmaceutical industries. These are also used in the formation of many substances such as ammonia, nitric acid, and sulphuric acid.

Enzymes are biological catalysts that increase the rate of chemical reactions. These are highly specific in nature. Most enzymes are proteins. These increase the rate of reaction by decreasing the activation energy. Catalase is a common enzyme that catalyzes the decomposition of hydrogen peroxide to water and oxygen.

The given reaction occurs as follows:

$2{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\xrightarrow{{{\text{Catalase}}}}2{{\text{H}}_{\text{2}}}{\text{O}} + {{\text{O}}_{\text{2}}}$

Here, catalase catalyzes the decomposition of hydrogen peroxide and result in the formation of water and oxygen. Bubbles are formed due to production of oxygen gas during the reaction.

Learn more:

1. Which of these is an extensive property? brainly.com/question/1398514

2. Which of the phase changes is an exothermic change? brainly.com/question/1875234

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Catalysis

Keywords: catalyst, enzyme, catalase, water, oxygen, hydrogen peroxide, H2O2, H2O, O2, 2H2O2, 2H2O, decomposition, bubbles, biological catalysts, specific, proteins, chemical reactions.

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yuradex [85]

Um because of the energy in the heat? XD idk

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3 years ago

Can someone solve this for me I'm confused.

Artemon [7]

Answer:

310.53 g of Cu.

Explanation:

The balanced equation for the reaction is given below:

CuSO₄ + Zn —> ZnSO₄ + Cu

Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:

Molar mass of CuSO₄ = 63.5 + 32 + (16×4)

= 63.5 + 32 + 64

= 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of Cu = 63.5 g/mol

Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g

Summary:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.

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6 0

3 years ago

When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati

babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

$MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}$

Here, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 1
Cl = 1

Number of atoms on product side are as follows.

Mn = 1
O = 1
H = 2
Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply $H_{2}O$ by 2 on product side. Therefore, the equation can be rewritten as follows.

$MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$

Hence, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Number of atoms on product side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

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3 years ago

Two or more assistance

Goryan [66]

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