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Crank
3 years ago
11

What caused the bubbles to form when you added the catalase to the hydrogen peroxide and water mixture at 40 °c?

Chemistry
2 answers:
Dahasolnce [82]3 years ago
7 0
<span>What caused the bubbles to form when you added the catalyses to the hydrogen peroxide and water mixture at 40 °C? A. Catalyses activity heated the solution to its boiling point. B. Hydrogen gas formed during the formation of hydrogen peroxide. C. Oxygen gas formed during the decomposition of hydrogen peroxide.

This would be the water, mixture.</span>
Mrac [35]3 years ago
4 0

\boxed{{\text{Formation of oxygen}}} caused the bubbles to form when catalase is added to the hydrogen peroxide and water mixture at 40\;^\circ {\text{C}}.

Further explanation:

Catalyst:

These are the substances that change the rate of a chemical reaction but these don’t get consumed in the reaction. These have wide applications in petroleum, fertilizer and pharmaceutical industries. These are also used in the formation of many substances such as ammonia, nitric acid, and sulphuric acid.

Enzymes are biological catalysts that increase the rate of chemical reactions. These are highly specific in nature. Most enzymes are proteins. These increase the rate of reaction by decreasing the activation energy. Catalase is a common enzyme that catalyzes the decomposition of hydrogen peroxide to water and oxygen.

The given reaction occurs as follows:

2{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\xrightarrow{{{\text{Catalase}}}}2{{\text{H}}_{\text{2}}}{\text{O}} + {{\text{O}}_{\text{2}}}

Here, catalase catalyzes the decomposition of hydrogen peroxide and result in the formation of water and oxygen. Bubbles are formed due to production of oxygen gas during the reaction.

Learn more:

1. Which of these is an extensive property? brainly.com/question/1398514

2. Which of the phase changes is an exothermic change? brainly.com/question/1875234

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Catalysis

Keywords: catalyst, enzyme, catalase, water, oxygen, hydrogen peroxide, H2O2, H2O, O2, 2H2O2, 2H2O, decomposition, bubbles, biological catalysts, specific, proteins, chemical reactions.

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two people start out 100 meters apart from each other and start moving towards each other at the same time. One person is moving
andreev551 [17]

Answer:

1.332 meters per second. // 2.664 meters per second.

Explanation:

the slower person moved 33.3 meters, and the faster person moved 66.6 meters.

the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds

slower person moved 33.3/25 = 1.332 meters per second.

faster person moved 66.6/25 = 2.664 meters per second.

4 0
3 years ago
A small positively charged ball is moved closer to a large, positively charged ball. which describes how the small ball likely r
tankabanditka [31]

Answer:

This is just my guess, but since opposites attract, then im guessing that alikes repel each other. So, they will go away from each other when the ball is released (I think).

Explanation:

Hope this helps! If it did, please mark it as brainliest! It would help a lot! Thanks! :D

7 0
3 years ago
Helpppp pleaseee ill give brainliest
Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

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5 0
3 years ago
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Alex787 [66]

Answer:

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Explanation:

KBr + MgF₂ –> KF + MgBr₂

The above equation can be balance as illustrated below:

KBr + MgF₂ –> KF + MgBr₂

There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:

KBr + MgF₂ –> 2KF + MgBr₂

There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:

2KBr + MgF₂ –> 2KF + MgBr₂

Now, the equation is balanced.

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Nutka1998 [239]

Answer:

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Explanation:

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