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Marizza181 [45]
3 years ago
13

A dependent variable is

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

a variable (often denoted by y) whose value depends of that of another.

Explanation:

on g00gle duhh just look it up. :)

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Hurry need the answer asap
Soloha48 [4]

P,T,Y refers to the set of points which are collinear and is therefore denoted as option C.

<h3>What are Collinear points?</h3>

This is commonly used in geometry and refers to the set of points which lie on the same straight line and are always close to each other when compared to other points. It is possible for them to appear on different planes only and the value by the triangle from the three points is usually zero.

In the example give, only P,T and Y are the points which lie on the same line while other options have points which lie on different lines thereby making them incorrect.

This is therefore the reason why option C was chosen as the most appropriate choice.

Read more about Collinear points here brainly.com/question/18559402

#SPJ1

7 0
2 years ago
Momentum is. __________
horrorfan [7]
 is the product of the mass and velocity of an object, quantified in kilogram-meters per second. 
7 0
3 years ago
Select all of the following which are examples of physical change.
Vladimir79 [104]
Change of appearance, change in size and shape of a substance, change in phase of a substance, and I'm pretty sure expansion/contraction is an answer, too.
3 0
3 years ago
All the elements in a particular group of the periodic table have the same number of
FrozenT [24]
The answer is C. Valence Electrons
3 0
3 years ago
Read 2 more answers
How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?
devlian [24]

<u>Answer:</u> The amount of energy required to raise the given amount of temperature is 6400 J

<u>Explanation:</u>

To calculate the heat absorbed by the lead, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of lead = 200 g

c = heat capacity of lead = 0.128 J/g°C

\Delta T = change in temperature = 250°C

Putting values in above equation, we get:

q=200g\times 0.128J/g^oC\times 250^oC=6400J

Hence, the amount of energy required to raise the given amount of temperature is 6400 J

4 0
3 years ago
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