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3 years ago

Advantages for building on the green hill

Chemistry

2 answers:

Ksenya-84 [330]3 years ago

8 0

Flooding - Some places in Green Hill have steep areas and don't have any steep areas.

Minchanka [31]3 years ago

6 0

I think that building on a green hill

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What is the name of the molecule below?

SIZIF [17.4K]

Answer:

C.) 2-butyne

Explanation:

Since the molecule has 4 central carbons, it has the prefix but-.

Since the molecule has a triple bond between central carbons, it has an ending of -yne.

Since the triple bond starts on the second carbon, it has a 2 - prefix.

3 0

3 years ago

1.As per the Aufbau principle, which of the following orbitals have the lowest energy?

madam [21]

The correct answer attached in file, Thank you for joining brainly community.

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2 years ago

How much mass defect is required to release 5.5 x 1020 J of energy?

Montano1993 [528]

Answer : The mass defect required to release energy is 6111.111 kg

Explanation :

To calculate the mass defect for given energy released, we use Einstein's equation:

$E=\Delta mc^2$

E = Energy released = $5.5\times 10^{20}J$

$\Delta m$ = mass change = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in above equation, we get:

$5.5\times 10^{20}Kgm^2/s^2=\Delta m\times (3\times 10^8m/s)^2$

$\Delta m=6111.111kg$

Therefore, the mass defect required to release energy is 6111.111 kg

5 0

3 years ago

In a spacecraft tge carbon dioxide exhaled by the astronaut can be removed by the reaction with lithium hydroxide, LiOH accordin

quester [9]

Answer:

30 moles

Explanation:

From the equation it is a one - to - one reaction

3 0

2 years ago

When Iodine-131 emits a β particle (beta particle), what nuclide is produced? *

k0ka [10]

When Iodine-131 emits a β particle will produce Xe-131

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,

alpha α particles ₂He⁴
beta β ₋₁e⁰ particles
gamma particles ₀γ⁰
positron particles ₁e⁰
neutron ₀n¹

So for reaction Iodine-131 :

$\tt _{53}^{131}I\rightarrow _{-1}^0\beta +_{54}^{131}Xe$

5 0

3 years ago

Read 2 more answers