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4 years ago

Advantages for building on the green hill

Chemistry

2 answers:

Ksenya-84 [330]4 years ago

8 0

Flooding - Some places in Green Hill have steep areas and don't have any steep areas.

Minchanka [31]4 years ago

6 0

I think that building on a green hill

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How is matter and energy conserved in this chemical reaction?

finlep [7]

Answer:

The ratio of reactants and products in a chemical reaction is called chemical stoichiometry . Stoichiometry depends on the fact that matter is conserved in chemical processes, and calculations giving mass relationships are based on the concept of the mole . One mole of any element or compound contains the same number of atoms or molecules, respectively, as one mole of any other element or compound.

Explanation:

Hope this helps :)

5 0

3 years ago

For a galvanic cell that uses the following two half-reactions, Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l) Pb(s) → P

polet [3.4K]

Answer:

Explanation:

The detailed solution is found in the image attached. It is necessary to note that the oxidation half equation is multiplied by three to balance electron gain and loss. This is adequately shown in the image below. Inferences are only drawn from balanced redox reaction equation hence the first step is to balance the redox reaction equation.

5 0

4 years ago

What is the formula for a hydrate that contains 5.99 g CuSO4 and 5.4 g H2O?

adoni [48]

A hydrate is a chemical that has water molecules loosely bonded to it. The water molecules are not ... You will be using the hydrate CuSO4 . ?H2O. Sample Calculation-. An empty crucible has a mass of 12.770 grams.

8 0

3 years ago

Consider the following reaction:

ruslelena [56]

<u>Answer:</u> The rate of the reaction when concentrations are changed is $5.17\times 10^{-2}M/s$

<u>Explanation:</u>

For the given chemical reaction:

$A+B+C\rightarrow D$

The given rate law of the reaction follows:

$\text{Rate}_1=k\frac{[A][C]^2}{[B]^{1/2}}$

We are given:

$\text{Rate}_1=1.12\times 10^{-2}M/s$

When the concentrations are changed:

New concentration of A = 2A (Concentration is doubled)

New concentration of C = 2C (Concentration is doubled)

New concentration of B = 3B (Concentration is tripled)

The new rate law expression becomes:

$\text{Rate}_2=k\frac{[2A][2C]^2}{[3B]^{1/2}}\\\\\text{Rate}_2=\frac{2\times 2^2}{3^{1/2}}\times (k\frac{[A][C]^2}{[B]^{1/2}})\\\\\text{Rate}_2=4.62\times (\text{Rate}_1)\\\\\text{Rate}_2=4.62\times 1.12\times 10^{-2}\\\\\text{Rate}_2=5.17\times 10^{-2}M/s$

Hence, the rate of the reaction when concentrations are changed is $5.17\times 10^{-2}M/s$

8 0

4 years ago

Water is a compound.Why?

AlekseyPX

Answer:

Explanation:

Water made up from 2 different molecules

3 0

3 years ago

Read 2 more answers