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3 years ago

Advantages for building on the green hill

Chemistry

2 answers:

Ksenya-84 [330]3 years ago

8 0

Flooding - Some places in Green Hill have steep areas and don't have any steep areas.

Minchanka [31]3 years ago

6 0

I think that building on a green hill

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Do all forms of radioactive decay change the identity of the original element?

hoa [83]

Explanation:

<h3>yes, Radioactive decay involves the emission of a particle and/or energy as one atom changes into another. In most instances, the atom changes its identity to become a new element.</h3>

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2 years ago

Which of the following is used to show sound waves?

Ipatiy [6.2K]

I think it’s c bc it makes more sense

3 0

2 years ago

How would this change affect the food web?check all that apply

klio [65]

During the summer, when the land is brown and the grass is green, the population of mice decreases because mice are easily spotted by the organisms that eat them.

How would this change affect the food web? Check all that apply.

A. It will increase the grass population.

D. It will decrease the snake population

E. It will increase the grasshopper population

hope this helps! If so please mark brainliest and rate/heart to help my account if it did!!

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3 years ago

If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?

ss7ja [257]

Answer:

$V=22.4L$

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm} \\\\V=22.4L$

Best regards.

4 0

3 years ago

Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s)

klemol [59]

Answer:

a) 2.01 g

Explanation:

Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:

0.0302 mol AgNO₃ * $\frac{1molNa_2CO_3}{2molAgNO_3}$ = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:

0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

8 0

3 years ago