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3 years ago

Tell me correct answer I wrote wrong show work give me correct answer and get 20 points

Mathematics

2 answers:

Vlad1618 [11]3 years ago

8 0

I think it would be c because you are looking for the answer i think

Lemur [1.5K]3 years ago

8 0

It's a you are dividng the whole (3 and 1/4) by 3/4 and you get 1/4 left over.

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I need help please!

Vlad1618 [11]

Answer:

$\Huge \boxed{y=3x+6}$

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

The slope can be found from two points.

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

The two points from the graph are (1, 9) and (2, 12).

Plugging in the values and evaluating.

$\displaystyle m=\frac{12-9}{2-1}$

$\displaystyle m=\frac{3}{1}$

$m=3$

The slope of the line is 3.

The y-intercept of the line is where the line cross the y-axis.

The line crosses the y-axis at (0, 6).

$b=6$

The slope-intercept form of the line is:

$y=3x+6$

8 0

3 years ago

250 grams of sugar cost 150 dollars at Shop X. 100 grams of sugar cost 95 dollars at Shop Y. What is the difference in cost per

nata0808 [166]

<h2>Answer:</h2>

350 dollars

<h2>Step-by-step explanation:</h2>

<em>(step 1) Find the cost per kilogramme of sugar in shop X</em>

In shop X:

250 grams of sugar costs 150 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 250 grams will be equal to 0.25 kilogramme

Therefore (replacing 250 grams with 0.25 kilogramme) in shop X;

0.25 kilogramme of sugar costs 150 dollars

Now, if

0.25 kilogramme = 150 dollars,

=> 1 kilogramme = 150 dollars x 1 kilogramme / 0.25 kilogramme

=> 1 kilogramme = 600 dollars

Therefore, the cost per kilogramme of sugar in shop X is 600 dollars

<em>(step 2) Find the cost per kilogramme of sugar in shop Y</em>

In shop Y:

100 grams of sugar costs 95 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 100 grams will be equal to 0.1 kilogramme

Therefore (replacing 100 grams with 0.1 kilogramme) in shop Y;

0.1 kilogramme of sugar costs 95 dollars

Now, if

0.1 kilogramme = 95 dollars,

=> 1 kilogramme = 95 dollars x 1 kilogramme / 0.1 kilogramme

=> 1 kilogramme = 950 dollars

Therefore, the cost per kilogramme of sugar in shop Y is 950 dollars

<em>(step 3) Find the difference in cost per kilogramme of sugar between the two shops</em>

The difference is calculated by subtracting the cost per kilogramme of sugar in shop X from the cost per kilogramme of sugar in shop Y. i.e

=> cost per kilogramme of sugar in shop Y - cost per kilogramme of sugar in shop X

=> 950 dollars - 600 dollars

=> 350 dollars.

Therefore, the difference in cost per kilogramme is 350 dollars

3 0

2 years ago

Jason runs the same distance each day. In one 7-day period he ran 40 1/4 miles. He knows that there is a proportional relationsh

Harrizon [31]

Jason runs the same distance each day. In one 7-day period he ran 40 1/4 miles. He knows that there is a proportional relationship between n, the number of days, and t, the total distance he runs. Tell whether each statement is True or False.
A. The relationship can be expressed as n=5.25t. True or False
B. The graph of the equation is a straight line through (0,0). True or False
C. The unit rate is 5.75. True or False

The answer is A

7 0

3 years ago

Used use euler's method with step size 0.1 to estimate y(0.5), where y(x) is the solution of the initial-value problem y ' = y +

brilliants [131]

We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.

To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h

1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1

2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04

3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232

4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258

5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593

Answer: y(0.5) = 1.4593

4 0

3 years ago

How are transformations affected by specific values of a constant

OverLord2011 [107]

Adding a constant term to the value of a function could either result to an upward or downward shifts. On the other hand, it may also shift to left or to the right. Functions play a role on transformation as it will display how the graph is moved around.

8 0

3 years ago