We have to determine the value of 
= (5(9)+6) + (5(10)+6) +(5(11)+6) + .......... + (5(21)+6)
= 51+56+61+66+ ........ + 111
Since, the common difference is 5, hence this series is in arithmetic progression.
Sum of AP is given by the formula:
![\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Since, there are 13 terms.
= ![\frac{13}{2}[2(51)+(13-1)5]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B2%2851%29%2B%2813-1%295%5D)
= ![\frac{13}{2}[102+60]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B102%2B60%5D)
= ![\frac{13}{2}[162]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B162%5D)
= 
= 1053
Therefore, the sum of the series is 1053.
So, Option G is the correct answer.