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3 years ago

The table shows different geologic time periods:

Mathematics

2 answers:

luda_lava [24]3 years ago

8 0

The time periods from oldest to youngest:
Silurian
Triassic
Jurassic
<span>Tertiary</span>

enyata [817]3 years ago

8 0

2.08 x 10^8 = 208,000,000
4.38 x 10^8 = 438,000,000
6.64 x 10^7 = 66,400,000
2.45 x 10^8 = 245,000,000

<span>oldest to youngest : Silurian, Triassic, Jurassic, Tertiary</span>

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Which pair of measurements is not equivalent? 24 feet, 8 yards 24 inches, 2 feet 10 feet, 120 inches 3 miles, 15,480 feet

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12,480 feet is not equal to three miles

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3 years ago

HELP ASAP

Sindrei [870]

Answer:

median = 27

range = 29

mode = 32

maximum value = 41

interquartile range = 21

minimum = 12

upper quartile = 35

mean = 25

lower quartile = 14

Step-by-step explanation:

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Saul has 8 bags. He records the weight of each bag on the line plot.

Naddika [18.5K]

Answer:

Step-by-step explanation:

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3 years ago

Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

4 years ago

8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm

Ilya [14]

Answer:

a₁ = 38

Step-by-step explanation:

Given AP, where:

8a₈ = 12a₁₂
d = -2,
a₁ = ?

=============

<h3>Solution</h3>

aₙ = a₁ + (n-1)d

a₈ = a₁ + 7d = a₁ + 7*(-2) = a₁ - 14
a₁₂ = a₁ + 11d = a₁ + 11*(-2) = a₁ - 22

8a₈ = 12a₁₂

8(a₁ - 14) = 12(a₁ - 22)
2(a₁ - 14) = 3(a₁ - 22)
2a₁ - 28 = 3a₁ - 66
3a₁ - 2a₁ = -28 + 66
a₁ = 38

6 0

3 years ago