Answer:
Check the attached graph
Step-by-step explanation:
Given equation is
.
Now we need to graph the given equation
..
Clearly it is not linear as equation is not of the form
. So we need to find some points on given equation
. by plugging some random values of x like -5,-3,1,... etc.
for x=-5, we get:

.
Hence first point is at (-5,-2). Similarly we can find more points and graph those points.
x can't be 0 as division by 0 is not defined so it will have vertical asymptote at x=0.
Since degree of numerator is less than degree of denominator so y=0 will be horizontal asymptote.
Now join those points by a curved line to get final graph.
Answer: 36 sec
Step-by-step explanation:
Let
x------> distance the kitten runs before being caught by the puppy
Remember that
The speed is equal to divide the distance by the time
v=d/t
solve for t
t=d/v
so
equate the time
x/20=(180+x)/25
25x=20(180+x)
25x=3,600+20x
25x-20x=3,600
x=3,600/5=720 m
t=d/v=720/20=36 sec
or
t=(720+180)/25=900/25=36 sec
Answer:i need this answer
Step-by-step explanation:
Answer: (110.22, 125.78)
Step-by-step explanation:
The confidence interval for the population mean is given by :-

Given : Sample size = 463


Significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 90% confidence interval for the population mean will be :-

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)
Answer:
x = 8
Step-by-step explanation:
you have similar triangles here
so 2 is to 4 as 4 is to x
2/4 = 4/x
x = 8