9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
Answer:
x = -2+√3i and -2-√3i
Step-by-step explanation:
The formula for the general formula is expressed as;
x = -b±√b²-4ac/2a
Given the expression
x²+4x+7 = 0
a = 1, b = 4 and c = 7
Substitute
x = -4±√4²-4(1)(7)/2(1)
x = -4±√16-28/2
x = -4±√-12/2
x = -4±√4*-3/2
x = -4±2√-3/2
x = -4±2√3i/2
x = -4+2√3i/2 and -4-2√3/2
x = -2+√3i and -2-√3i
a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is
b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so
c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so
Then by linearity, we have
Okay! I drew the graph and I got Point Q is 0.1 unit to the right of 1.
Knowing the order of the numbers is the best way to get the answer.
