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3 years ago

Basic math

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

Answer:

The quotient contains a terminating decimal and The quotient is a whole number less than 11.

Step-by-step explanation:

To answer this one, it's mandatory to remember that quotient, is the outcome of a ratio: a number (r) over another (s) (different than 0). In this case: $\frac{81}{918}$ . So q is equal to =0.08823529411.

Analyzing the number: 0.08823529411

This is not a repeating decimal, but it is a terminating decimal for it has an end.

The quotient is also a whole number less than 11.

The Whole Set of numbers is made up of the following numbers W ={0,1,2,...} and 0 < 11. Therefore it is true.

Aliun [14]3 years ago

5 0

Answer:

The quotient contains a terminating decimal and The quotient is a whole number less than 11.

Step-by-step explanation:

To answer this one, it's mandatory to remember that quotient, is the outcome of a ratio: a number (r) over another (s) (different than 0). In this case:. So q is equal to =0.08823529411.

Analyzing the number: 0.08823529411

This is not a repeating decimal, but it is a terminating decimal for it has an end.

The quotient is also a whole number less than 11.

The Whole Set of numbers is made up of the following numbers W ={0,1,2,...} and 0 < 11. Therefore it is true.

Step-by-step explanation:

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3 years ago

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Question 17 please help

kramer

$\sqrt{9x^2} / \sqrt{18y^2}$
after taking sqrt both side

3x/ $\sqrt{9*2y^2}$

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
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Answer is A

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3 years ago

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.