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nataly862011 [7]
3 years ago
7

Basic math

Mathematics
2 answers:
LenKa [72]3 years ago
8 0

Answer:

The quotient contains a terminating decimal and The quotient is a whole number less than 11.

Step-by-step explanation:

To answer this one, it's mandatory to remember that quotient, is the outcome of a ratio: a number (r) over another (s) (different than 0). In this case:\frac{81}{918}. So q is equal to =0.08823529411.

Analyzing the number: 0.08823529411

This is not a repeating decimal, but it is a terminating decimal for it has an end.

The quotient is also a whole number less than 11.

The Whole Set of numbers is made up of the following numbers W ={0,1,2,...} and 0 < 11. Therefore it is true.

Aliun [14]3 years ago
5 0

Answer:

The quotient contains a terminating decimal and The quotient is a whole number less than 11.

Step-by-step explanation:

To answer this one, it's mandatory to remember that quotient, is the outcome of a ratio: a number (r) over another (s) (different than 0). In this case:. So q is equal to =0.08823529411.

Analyzing the number: 0.08823529411

This is not a repeating decimal, but it is a terminating decimal for it has an end.

The quotient is also a whole number less than 11.

The Whole Set of numbers is made up of the following numbers W ={0,1,2,...} and 0 < 11. Therefore it is true.

Step-by-step explanation:

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just olya [345]

Step-by-step explanation:

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5 0
3 years ago
What is square root of 167?
enot [183]
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Hope this helps :)
7 0
3 years ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
A 5x5 table is filled with numbers (one number per cell). It is known that the product of 5 numbers in each column is negative.
Advocard [28]

Answer:

Yes

Step-by-step explanation:

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5 0
2 years ago
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antoniya [11.8K]

Answer:

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Step-by-step explanation:

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