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insens350 [35]
4 years ago
11

Hello Can you help please find the answer c ?

Mathematics
2 answers:
lawyer [7]4 years ago
7 0

Answer:

150 i think

Step-by-step explanation:

hope this helps if it doesnt im soooo sorrry

Ivahew [28]4 years ago
7 0
I think it might be 90°
But I’m not sure, sorry if this is wrong! :(
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4 years ago
Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

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Rewrite the given transform as

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Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

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3 years ago
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