Answer:
<h3>a) 5 flowers</h3><h3>b) Trapezoid</h3>
Step-by-step explanation:
For one flower, the following shapes are used;
6 yellow hexagons, 2 red trapezoids and 9 green triangles
If we are given 30 yellow hexagons 50 red trapezoids and 60 green triangles, to get the number of flowers we can make, we will find the greatest common factor of 30, 50 and 60
30 = 6*5
50 = (2*5)+40
60 = (9*5)+15
We can see that 5 is common to all the factors. This means that we can make 5 flowers if they were changed to 30 yellow hexagons 50 red trapezoids and 60 green triangles.
Since there are 40 trapezoids left and 15 green triangles left, hence the shape that would have n as left over most is trapezoid (40 left over)
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
Answer:
Step-by-step explanation:4 -2x=3x +2
4-2=3x+2x
2=5x
X=2/5
Answer:
A Parallelogram
Step-by-step explanation:
Answer:
y = - x + 9
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = 
with (x₁, y₁ ) = (0, 9) and (x₂, y₂ ) = (9, 0) ← 2 points on the line
m = 
= 
= - 1
the line crosses the y- axis at (0, 9 ) ⇒ c = 9
y = - x + 9 ← equation of line
