Explanation:
For the given reaction
Now, expression for half-life of a second order reaction is as follows.
....... (1)
Second half life of this reaction will be . So, expression for this will be as follows.
= ...(2)
where is the final concentration that is, here and is the initial concentration.
Hence, putting these values into equation (2) formula as follows.
=
= ...... (3)
Now, dividing equation (3) by equation (1) as follows.
=
= 3
or, = 3
Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.
Answer:
7g/cm³
Explanation:
Given parameters:
Mass of the mineral = 21g
Volume = 3cm³
Unknown:
Density of the mineral = ?
Solution:
Density of a substance is the mass per unit volume of the substance.
Density =
Now insert the given parameters and solve;
Density = = 7g/cm³
The mineral with a density of 7g/cm³ is Galena, an ore of lead.
<span><span>NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution = 22.4 mlNumber of HCl moles = (2mol/1000 ml)*22.4 ml = 0.0448 mol</span></span>
The catalyst has been represented with the formula above the arrow in the chemical equation.
The catalyst has been the compound or element in the chemical reaction that helps in the lowering of the activation energy of the system and thereby leads to an increase in the rate of the reaction.
The chemical equation has been represented in the form of the chemical formula of the reactants and the products.
The catalyst has not been consumed in the chemical reaction, thus it has been represented with the formula above the arrow in the chemical equation.
For more information about the catalyst, refer to the link:
brainly.com/question/17052831
Answer:
7.5 x 10 ^-11
Explanation:
6/8 = .75
10^2 / 10^12 = 10^ (2-12) = 10^(-10)
so far .75 x 10^-10
which is 7.5 x 10^-11