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Natasha2012 [34]
3 years ago
10

mercury has a density of 13.6g/mol what volume of mercury must be taken to obtain 225g of the metal ​

Chemistry
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

16.54 mL

Explanation:

From the question;

  • Density of mercury of 13.6 g/mL
  • Mass of the mercury metal is 225 g

We are needed to determine the volume of the mercury metal;

We need to know that;

  • Density is given by dividing the mass of a substance by its volume.

That is;

Density = Mass ÷ Volume

Rearranging the formula;

Volume = Mass ÷ Density

Therefore;

Volume = 225 g ÷ 13.6 g/mL

             = 16.54 mL

Thus, the volume of the mercury needed is 16.54 mL

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3 years ago
Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)
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Suppose there are 100 moles in solution:

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Density of solution = D

S.G=\frac{D}{d_w}

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D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL

Mass of the solution = 588 g + 1692 g = 2280 g

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=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L

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Molarity = \frac{n}{V(L)}

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L

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