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myrzilka [38]
3 years ago
5

The Nernst equation at 20oC is:

Chemistry
1 answer:
saw5 [17]3 years ago
5 0

Answer:

a. -58 millivolts

Explanation:

The given Nernst equation is:

E_{ion} = 58 millivolts /z \Big[ log_{10} \Big( \dfrac{[ion]_{out}}{[ion]_{in}}\Big) \Big]}

The equilibrium potential given by the Nernst equation can be determined by using the formula:

E_{Cl^-} = \dfrac{2.303*R*T}{ZF} \times log \dfrac{[Cl^-]_{out}} {[Cl^-]_{in}}

where:

gas constant(R) = 8.314 J/K/mol

Temperature (T) = (20+273)K

= 298K

Faraday constant F = 96485 C/mol

Number of electron on Cl = -1

E_{Cl^-} = \dfrac{2.303*8.314*298} {(-1)*(96845)} \times log \dfrac{100} {10}

E_{Cl^-} = - 0.05814  \ volts

\mathsf{E_{Cl^-} = - 0.05814  \times 1000 \  milli volts}

\mathsf{E_{Cl^-} \simeq - 58\   milli volts}

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