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KATRIN_1 [288]
2 years ago
15

What is the equilibrium constant for the reaction?

Chemistry
1 answer:
sp2606 [1]2 years ago
7 0

Answer: C. 20

Explanation: One equation for the equilibrium constant is \frac{[Products]}{[Reactants]}. The products are typically on the left side and the reactants on the right.

Given this and the values of each, we can easily plug this in. However, we must multiply the products instead of adding them.

\frac{0.69M*0.98M}{0.034M} =19.888, or 20M

19.888 can be easily rounded to 20, meaning that C is the best answer.

I hope this helps! Pls mark brainliest!! :)

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t = 10 mm / ( 1 mm / s )
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The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as 2NI3(s)→N2(g)+3I2(g)
EastWind [94]

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According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

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-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

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