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Nata [24]
3 years ago
6

What shape has this many sides 44mm,28mm,24mm and 110 angles,40 angles,and 30 angles

Mathematics
2 answers:
Shalnov [3]3 years ago
3 0
<span>Hexagon - 6 sides im not sure if thats what you need</span>
Natali5045456 [20]3 years ago
3 0
A shape with three sides and three angles is a triangle. An obtuse triangle to be more exact
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Help please I don't understand.........
frez [133]
Given the graph, you can assume that f(x) is the y of an equation.

When f(2) is given, this means that what is the y value when x=2?

As you can see, the solution is between 8 and 10. Meaning that the closest answer is 9.

Hope I helped :)
6 0
3 years ago
in the number 8.88, how is the value of the underlined digit related to the digits on its left and right?
nikklg [1K]
Digits on the right are like units and digits on the left are like tenths
7 0
2 years ago
Find the length of a diagonal of a square with sides 10in. long
Ghella [55]
Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
{x}^{2}  +  {x}^{2}  =  {10}^{2}
2 {x}^{2}  = 100
{x }^{2}  = 50
x =  \sqrt{50}
side of a diagonal=2 sqrt50
= 10 \sqrt{2}
cm......



HOPE IT HELPS YOU '_'
3 0
3 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
**GIVING OUT BRAINLIEST PLEASE HELP***
OLga [1]

Answer:

n is less than or equal to: 10

Step-by-step explanation:

10n+20=120

subtract 20

10n=100

divide by 10

n=10

7 0
3 years ago
Read 2 more answers
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