(2y+3)(3y^2+4y+5)
so u just multiply all the things from different brackets.
2y*3y^2 = 6y^3
2y*4y = 8y^2
2y*2 = 4y
3*3y^2 = 9y^2
3*4y = 12y
3*5 = 15
so 6y^3+8y^2+4y+9y^2+12y+15
thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:
6y^3+17y^2+16y+15
i hope this helps :)
someone correct me if im wrong
Substitution method is one of the ways to solve this system.
-5x+y=4 and 4x-4y=16.
First we will divide the second equation with number 4 and get
x-y=4 => x=y+4 than we will replace x in the first equation
-5(y+4)+y=4 => -5y-20+y=4 => -4y=4+20 => -4y=24 => y=-6
x-(-6))=4 => x+6=4 => x=4-6=-2 (x,y)=(-2,-6)
Good luck!!!
Answer:
70
Step-by-step explanation:
Because PQ tangent to circle, angle P is 90
angle S = 180 - 90 - 20 = 70
343 = 7*7*7, so the square root is 7*sqrt(7), because there is one 7 left in the square root after taking out the other 2.
Final answer:
7*sqrt(7), or about 18.52
Hope I helped :)
