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rodikova [14]
2 years ago
9

Michael has interviewed for two jobs. He feels that he has a 50% chance of getting an offer on Job A and a 60% chance of getting

an offer on Job B. He also believes there is a 30% chance of getting an offer on both jobs. What is the probability that he receives an offer on at least one of the jobs?
A. 0.70
B. 0.25
C. 0.10
D. 0.80
Mathematics
1 answer:
shutvik [7]2 years ago
5 0

Using Venn probabilities, it is found that the probability that he receives an offer on at least one of the jobs is given by:

D. 0.80

<h3>What is a Venn probability?</h3>

In a Venn probability, two non-independent events are related with each other, as are their probabilities.

The "or probability" is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

In this problem, we have that:

  • 50% chance of getting an offer on Job A, hence P(A) = 0.5.
  • 60% chance of getting an offer on Job B, hence P(B) = 0.6.
  • 30% chance of getting an offer on both jobs, hence P(A \cap B) = 0.3.

Then, the probability of getting an offer on at least one job is:

P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.5 + 0.6 - 0.3 = 0.8

Hence option D is correct.

More can be learned about Venn probabilities at brainly.com/question/25698611

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<h2>Answer:</h2>

(a)

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(b)

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<h2>Step-by-step explanation:</h2>

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Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

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We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

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P(A\bigcap B)=\dfrac{1}{20}

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( since, there are just two outcomes such that the sum is: 9

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(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

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