7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
8 halls would be required to accommodate 520 people in the hall.
As we know that a hall can accommodate 65 people.
To determine the number of hall required for 520 people,
first we need to find that how many halls would be required for one person,
So, we will divide the 1 by 6 to find :
The number of one person accommodate = 1/65 Hall
Then, 520 people required to accommodate = 1/65 × 520
= 8 Halls.
[Accommodate: to have enough space for somebody/something, especially for a certain number of people]
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Answer:
36
Step-by-step explanation:
12 x 3 = 36
