Hi!
So we have to make a system of equations here.
Let sibling 1 be O and sibling 2 be Y (for older and younger)
So:
O + Y = 64
O = 64 - Y
(Either one works)
The older sibling is 6 years older.
O = Y + 6
Make everything in terms of Y.
64 - Y = Y + 6
Same to both:
58 = 2y
2y = 58
Divide by 2 on both sides:
y = 29
Since the older sibling is 6 years older:
29 + 6 = 35
Y = 29
O = 35
Let me know if you have any questions.
Answer:
x=2
x=-5
Step-by-step explanation:
You need to get everything on one side to have a quadratic equation:
x^2+6x-4 -(3x+6) = x^2+3x-10
All factors of 10 are 1*10 and 2*5.
5-2 = 3 and 5*-2 = -10
Factoring x^2+3x-10 gives us (x-2)(x+5)
x=2
x=-5
√x + 9 - 4 = 1
√x + 5 = 1
√x = -4
√x = √-4
x = 2i
787-10=777
777/3=259
259 multiples of 3
P(x)=2x 4 −x 3 +2x 2 −6P, left parenthesis, x, right parenthesis, equals, 2, x, start superscript, 4, end superscript, minus, x,
Tresset [83]
Answer:
P = -x^3 +12 / x+6
Step-by-step explanation:
Let's solve for p.
px=(2)(4)−x3+(2)(2)−6p
Step 1: Add 6p to both sides.
px+6p=−x3−6p+12+6p
px+6p=−x3+12
Step 2: Factor out variable p.
p(x+6)=−x3+12
Step 3: Divide both sides by x+6.p(x+6)
x+6
=
−x3+12
x+6
p=
−x3+12
x+6
