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timama [110]
3 years ago
14

Holly finds that (11m – 13n + 6mn) – (10m – 7n + 3mn) = m – 20n + 9mn. What error did Holly make?

Mathematics
2 answers:
Natalija [7]3 years ago
6 0

Answer:

she added 11 plus 10 wrong

Step-by-step explanation:

11 plus 10 = 21

gogolik [260]3 years ago
4 0

Answer: A ) She only used the additive inverse of 10m when combining like terms .

Step-by-step explanation:

Holly only used the additive inverse of 10m when combining like terms. The equality is erroneous because the equation was evaluated well. The calculations should be as follows:

11m -13n + 6mn - 10m + 7n - 3mn = 1m - 6n +3mn

She should have subtracted 13n and 7n then take the negative value. Also, subtract 6mn and 3mn.

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Answer:

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7 0
3 years ago
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A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle
hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

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Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

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3 years ago
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Answer:

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3 years ago
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