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iris [78.8K]
3 years ago
5

Pls help! I know it's not much points but I rlly need help! How do I translate this into an equation: Seven times the difference

of a number and 4 is no more than 10. I don't need it to be solved, I just need it to be written as an equation. plsss help ✨✨
Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

Is seven times the difference of a number and 4 no more than 10?

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The circle below is centered at the point (4,3) and has a radius length 5. What is its equation
Crazy boy [7]
The equation of a circle centred at point (m,n) and radius r is given by

<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5

Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0

The equation of the circle is x² + y² - 8x - 6y = 0

Hope it helps!
3 0
3 years ago
Read 2 more answers
Two lines interesting at a right angle​
schepotkina [342]

Answer:

Perpendicular lines are lines that intersect at right angles.

Step-by-step explanation:

I'm assuming that your question is asking what the term is for two lines that intersect at a right angle. If I'm correct then your answer is perpendicular lines.

Hope this helps

7 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
PLEASE HELP <br><br> ILL GIVE BRAINLIEST !
Naily [24]

answer:

to my knowledge it's, 65

5 0
3 years ago
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Solve for x.<br> 4 - 3x<br> 2<br> = 5<br> A) -2 <br> B) -<br> 1<br> 2<br> C) <br> 1<br> 2<br> D) 2
Fudgin [204]

Answer:

This problem was pasted incorrectly

Step-by-step explanation:


4 0
2 years ago
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