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iris [78.8K]
3 years ago
5

Pls help! I know it's not much points but I rlly need help! How do I translate this into an equation: Seven times the difference

of a number and 4 is no more than 10. I don't need it to be solved, I just need it to be written as an equation. plsss help ✨✨
Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

Is seven times the difference of a number and 4 no more than 10?

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Answer:

e

Step-by-step explanation:

The cube on the top, the one with the width of 4 is Cube 1.

The other one is Cube 2.

The length of the cube is 4, the width 2, and the height 5.

We know the length is 4 because we can look at the side, where both measurements 6 ft and 3 ft can be found.

We know that the height is 5 because for Cube 2, the height is 3. The total height is 8, so we subtract 3 from 8. We get our difference of 5.

V = l x w x h

V = (4)(2)(5)

V = (8)(5)

V = 40.

Cube 2 has a length is 6, the width 2, and the height 3.

V = l x w x h

V = (6)(2)(3)

V = (12)(3)

V = 36

We add the volumes of both cubes.

40 + 36 = 76

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Write a number that is greater than 714,587
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Read 2 more answers
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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