Number 14 on my integrated geometry test
2 answers:
You might be interested in
<u>Answer:</u>
Below!
<u>Step-by-step explanation:</u>
<u>The best way to answer this question is to read the statement carefully.</u>
- => Five less than twice a number = 2x - 5
- => Five times the sum of two numbers = 5(x + y)
- => The difference of 5 and a number, squared = (5 - x)²
Hoped this helped.
Answer:
(a)
(b)
Step-by-step explanation:
(a)
(3xy^3)(2x^3y)
- (3*2)(x*x^3)(y*y^3)
- (6)(x^4)(y^4)
(b)
This is just the rainbow method or as i like to call it the multiplication attack. All the terms in the first bracket fire themselves on the ones in the second. Each term attacks all the other terms once. Once they fire (multiply) they stick and can be added up. To make it easier i like to imagine them as squads.
(x^2 +2x +3)[x^2 -2x-4]
This can be expressed now as
(x^2 +2x +3)[x^2] + (x^2 +2x +3)[-2x] + (x^2 +2x +3)[-4]
Now to expand
x^4 + 2x^3 + 3x^2 -2x^3 -4x^2 - 6x -4x^2 - 8x - 12
Group like terms (same x powers)
(x^4) + (2x^3-2x^3) + (3x^2-4x^2-4x^2) + (- 6x-8x) + (-12)
Simplify