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Ket [755]
3 years ago
15

Which is the graph of f(x) =3(2/3)

Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Asbdjsjsjskisowiwiwj

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4 to the 3rd power - 3 to the 3rd power=
mylen [45]

Answer:

37

Step-by-step explanation:

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I need help with the whole homework and yeah plz answer and who ever answers gets a brainlist answer
pashok25 [27]

Answer:

1.) 357

2.) 221.5

3.) 72

4.) 1653

5.) 265

6.) 296

7.) 43.16

8.) 136

9.) 2486.33

10.)a. 48 b. 3

11.) 79

explantion: It breaks down a division problem into a series of easier steps. As in all division problems, one number, called the dividend, is divided by another, called the divisor, producing a result called the quotient.

https://www.theschoolrun.com/what-is-long-division

4 0
3 years ago
Find the solution of the system of equations.<br>- 3x + 10y = 17<br>3x + 7y = 17​
atroni [7]

Answer:

x=1, y=2. (1, 2).

Step-by-step explanation:

-3x+10y=17

3x+7y=17

---------------

17y=34

y=34/17

y=2

3x+7(2)=17

3x+14=17

3x=17-14

3x=3

x=3/3

x=1

5 0
3 years ago
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A truck is leaving a post office and heading out to deliver mail. The table shows the truck's distance d from the post office at
zalisa [80]

Answer:

eliver mail. The table shows the truck's distance d from the post office at time t. Calculate the average rate of change over the interval from 8 to 15 minutes. t(min) d (km) 0 0 8 7 11 11 15 14 22 16 (1 point) The rate of change is about 0.8 kilometers per minute. The rate of change is 7 kilometers

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3 years ago
e 400 trials in which the assistant maintained a neutral expression, the driver stopped in 229 out of the 400 trials. Find a 95%
Fittoniya [83]

Answer:

Step-by-step explanation:

n = 400

Proportion p = 229/400= 0.5725

For 95% confidence interval we use Z value as 1.96

Std error = 0.025

margin of error = 1.96*0.025

Confidence interval 95% = 0.5725±Margin of error

= (0.524, 0.621)

b) When smiled x becomes 277

p = 0.6925

Std error = 0.023

Margin of error= 1.96*0.023

Confidence interval = (0.647, 0.738)

Smiling increases the chances of stopping since mean and conidence interval bounds are showing increasing trend.

6 0
3 years ago
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