Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Answer:

Step-by-step explanation:
Given
The x and y values
Required
The regression line equation
Because of the length of the given data, I will run the analysis using online tools, then analyze the result.
From the analysis, we have:


--- Sum of squares
--- Sum of products
The regression equation is calculated as:

Where:

So, we have:




So:
becomes

Answer:
um hi I don't know what to say so I put a picture of my dog
Step-by-step explanation:
Sum of 20 terms in thr arithmetic sequence adds up to -1930
Answer:
About $4425.69
Step-by-step explanation:
Input the values into the equation to get: $4253(1+0.01)^4=
$4425.69(when rounding to the nearest cent)