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2 years ago

A line passes through the points (1, 4) and (3,-4). Which is the equation of the line?

Mathematics

1 answer:

andrew-mc [135]2 years ago

3 0

Answer:

Y=-4x+8

Step-by-step explanation:

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-2x + 8 = 18 please help. What does x equal

kakasveta [241]

Answer:

x = -5

Step-by-step explanation:

Step 1: Write equation

-2x + 8 = 18

Step 2: Solve for x

Subtract 8 on both sides: -2x = 10
Divide both sides by -2: x = -5

Step 3: Check

Plug in x to verify it's a solution.

-2(-5) + 8 = 18

10 + 8 = 18

18 = 18

6 0

2 years ago

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What is the answer for this equation?

puteri [66]

Is there a picture to go along with it? Because it's asking for the measure of ABD which is a triangle or a ray or something

6 0

3 years ago

Please help me thank you

Colt1911 [192]

Answer:

-2 $\frac{1}{10}$

Step-by-step explanation:

So this is simple substitution, $\frac{1}{2}$ (- $\frac{1}{5}$ )- $\frac{2}{3}$ (3)=> - $\frac{1}{10}$ - $\frac{6}{3}$ => $-\frac{1}{10}$ - 2= $-2\frac{1}{10}$ .

5 0

2 years ago

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A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .

Eduardwww [97]

Answer: $\bold{S_{\infty}=\dfrac{3125}{2}=1562.5}$

Step-by-step explanation:

a₁, 375, a₃, a₄, 81

First, let's find the ratio (r). There are three multiple from 375 to 81.

$375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}$

Next, let's find a₁

$a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625$

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

$S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}$

7 0

3 years ago

Calculate the circulation, \int_c\vec f\cdot d\vec r, in two ways, directly and using stokes' theorem. the vector field \vec f =

zubka84 [21]

\int_c\vec f\cdot d\vec r, in two ways, directly and using stokes' theorem. the vector field \vec f = 5 y\vec i - 5 x\vec j and c is the boundary of s, the part of the surface z = 16 -x^2-y^2 above the xy-plane, oriented upward.

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3 years ago