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3 years ago

11

What is 15.7 rounded to the nearest tenth? Sorry, I'm bad at math XD.

2 answers:

Artyom0805 [142]3 years ago

6 0

15.7 is already rounded to the nearest tenth.

Places:

... | tens | ones | decimal point | tenths | ...

Which for 15.7 is

... | 1 | 5 | . | 7 | ...

So you're good.

ale4655 [162]3 years ago

5 0

15.7 is already to the nearest tenth

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A right triangle has a height of 10 feet and an base of 4x^2y+2xy^2 feet. Find the area.show work to justify your answer (a=1/2)

dangina [55]

Givens
h = 10
b = 4x^y + 2xy^2

Formula
Area = 1/2 b * h

Solution
Substitute the givens into the formula
Area = 1/2 * 10 * (4x^2y + 2xy^2)
Area = 5 * (4x^2y + 2xy^2) What to do next? I would remove the brackets
Area = 5 * 4x^2y + 5 * 2xy^2
Area = 20x^2y + 10xy^2 <<<< Answer

Also possible is to take out more common factors.
The common factor of 4x^2y + 2xy^2 is 2xy and what is left over is 2x + y

So you would have Area = 5*2xy(2x + y)

If you have been given answers please list them.

5 0

3 years ago

The was question will be in the picture urgent please help

Katyanochek1 [597]

Answer:

A

Step-by-step explanation:

it's a scsle factor of 3.

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3 years ago

Read 2 more answers

A, B & C lie on a straight line.

slamgirl [31]

Answer:

x=38

Step-by-step explanation:

6 0

2 years ago

frozen [14]

Answer:

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

dividing both sides by 4

4y/4 = 3/4x - 7/4

y = 3/4x - 7/4

Now, comparing with the slope-intercept form of the line equation

y = 3/4x - 7/4

The slope of the line m = 3/4

We know that parallel lines have the same slopes.

Therefore, the slope of the parallel line is: 3/4

now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

$\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)$

$y+2=\frac{3}{4}\left(x+4\right)$

Thus, the equation in the point-slope form of the line equation is:

$y+2=\frac{3}{4}\left(x+4\right)$

Simplifying the equation

$y+2=\frac{3}{4}\left(x+4\right)$

Subtract 3 from both sides

$y+2-2=\frac{3}{4}\left(x+4\right)-2$

$y=\frac{3}{4}x+1$

Multiplying the equation by 4

$4y = 3x + 4$

$3x - 4y = -4$

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

7 0

3 years ago

When a fraction of 17 is taken away from 17 what remains exceeds 1/3 of 17 by 6

MrRissso [65]

1/3×17/1=51/1

51+6=57

4 0

3 years ago