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kipiarov [429]
3 years ago
8

Cara's Candles Cara likes candles. She also likes mathematics and was thinking about using algebra to answer a question she had

about two of her candles. Her taller candle is 16 cm tall. Each hour it burns makes the candle lose 2.5 cm in height. Her short candle is 12 cm tall and loses 1.5 cm in height for each hour that it burns.
Write an equation for both candles and solve it by either substitution or elimination.

(If someone could please help me out with this, I would really appreciate it. I've been trying to do this for days now and I just can't figure it out..)
(By the way, the equation for the 16 cm candle is y = -2.5x + 16, and the equation for the 12 cm candle is y = -1.5x + 12, I just don't know how to solve it using substitution or elimination.)​

please help I don't understand
I WILL give branliest to whoever's right
I really need the answers
Mathematics
1 answer:
Arlecino [84]3 years ago
7 0

Answer: Substitution

Step-by-step explanation: I think that because you have the equations already, you just have to solve for a variable using substitution. Do this by substituting one of the variables with another number. For example, make x=2 in both equations. Now you are free to solve for y and get your answer.

y=-2.5(2)+16

y=11

y=-1.5(2)+12

y=9

You can substitute in any number that makes it easy for you. Also, if you want x, you can substitute y. I'm really, really sorry if that is not helpful, I just told you what I know!

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3 years ago
Read 2 more answers
Which of the following represents the zeros of f(x) = x3 − 11x2 + 38x − 40?
Delvig [45]
The answer is <span>5, 4, 2
</span>
Among all choices we have 5, so
x = 5
x - 5 = 0
Let's divide the expression by (x - 5) using the long division:
                          x³ - 11x² + 38x - 40
(x - 5)  * x² =      x³ - 5x²                   Subtract
____________________________
                              -6x² + 38x - 40
   (x - 5) * (-6x) =    -6x² + 30x          Subtract
____________________________
                                           8x - 40
                    (x - 5) * 8 =     8x - 40   Sutract
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                                              0

Thus: x³ - 11x² + 38x - 40 = (x - 5)(x² - 6x + 8)

Now, let's simplify x² - 6x + 8.

x² - 6x + 8 = x² - 2x - 4x + 8 =
                  = x² - 2*x - (4*x - 4*2) = 
                  = x(x - 2) - 4(x - 2) =
                  = (x - 4)(x - 2)

Hence:
x³ - 11x² + 38x - 40 = (x - 5)(x - 4)(x - 2)
To calculate zero:
x³ - 11x² + 38x - 40 = 0
(x - 5)(x - 4)(x - 2) = 0
x - 5 = 0            or             x - 4 = 0              or      x - 2 = 0
x = 5                 or              x = 4                   or      x = 2
3 0
3 years ago
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Answer:

4/10 : 1/25

4/10 / 1/25 = 4/10 x 25/1 = 100/10 = 10.

10 can also be written as 10:1, so A is correct.

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6 0
2 years ago
Help plz will mark brainliest.
irina1246 [14]
AB = 24
BC = 45
AC = 51

cos C = adjacent / hypotenuse
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3 years ago
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tresset_1 [31]

Answer:

D.

Step-by-step explanation:

I am assuming they are not allowing graphing calculators for this, which is kind of wacky, if you ask me.

Anyway, the greater or equal to can technically be used interchangeably, so it looks like this:

y > 2x --> y = 2x

And so, with that equation, the sign just tells you what section of the graph is included. In this case, everything above the line.

4 0
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