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2 years ago

Which is an example of chemical weathering?

Chemistry

1 answer:

kobusy [5.1K]2 years ago

7 0

Answer:

b. the layer of oxide formed on statues made of metal

Explanation:

Chemical weathering is a process whereby rocks are disintegrated or weathered causing a chemical reaction thereby leading to change in the parent rock constituents .

In chemical weathering a new substance is usually formed after the weathering takes place.

From the question the layer of statue made by metal will likely form oxides of those metals. Example Silver will react with oxygen to form an entirely new substance like silver(i)oxide.

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Neon is a noble gas because it is stable non reactive and has ____ valence electrons

lesya692 [45]

Answer:

8 .....................

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3 years ago

Los hongos son bacterias?

malfutka [58]

Los hongos si son bacterias

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3 years ago

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madreJ [45]

Answer: All of these I’m pretty sure

Explanation: It just makes sense

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2 years ago

Compute the reactance of a 0.450 H inductor at the frequency of 60.0 Hz. Express your answer in ohms.

vlada-n [284]

Answer:

169.67Ω

Explanation:

This question is asking for the inductive reactance, which is calculated as follows:

X(L) = 2πfL

Where;

X(L) = inductive reactance (Ω)

f = frequency (Hz)

π = 3.142

L = inductance (Henry)

Given the information provided, f = 60Hz, L = 0.450H

X(L) = 2πfL

X(L) = 2 × 3.142 × 60 × 0.450

X(L) = 6.284 × 60 × 0.450

X(L) = 6.284 × 27

X(L) = 169.668

X(L) = 169.67Ω

7 0

3 years ago

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo

dimaraw [331]

Answer: The value of $K_c$ for given reaction is 0.465

Explanation:

We are given:

Initial concentration of A = 0.650 M

Initial concentration of B = 1.35 M

Initial concentration of C = 0.300 M

Equilibrium concentration of A = 0.550 M

Equilibrium concentration of B = 0.400 M

For the given chemical equation:

$A+2B\rightarrow C$

Initial: 0.65 1.35 0.30

At eqllm: 0.65-x 1.35-2x 0.30+x

Evaluating the value of 'x'

$0.650-x=0.550\\\\x=0.100$

So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M

Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M

The expression of $K_c$ for above equation follows:

$K_c=\frac{[C]}{[A][B]^2}$

Putting values in above equation, we get:

$K_c=\frac{0.400}{0.650\times (1.15)^2}\\\\K_c=0.465$

Hence, the value of $K_c$ for given reaction is 0.465

7 0

3 years ago