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Gre4nikov [31]
2 years ago
13

Which is an example of chemical weathering?

Chemistry
1 answer:
kobusy [5.1K]2 years ago
7 0

Answer:

b. the layer of oxide formed on statues made of metal

Explanation:

Chemical weathering is a process whereby rocks are disintegrated or weathered causing a chemical reaction thereby leading to change in the parent rock constituents .

In chemical weathering a new substance is usually formed after the weathering takes place.

From the question the layer of statue made by metal will likely form oxides of those metals. Example Silver will react with oxygen to form an entirely new substance like silver(i)oxide.

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Neon is a noble gas because it is stable non reactive and has ____ valence electrons
lesya692 [45]

Answer:

8 .....................

3 0
3 years ago
Los hongos son bacterias?
malfutka [58]
Los hongos si son bacterias
6 0
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Select the best answer.
madreJ [45]
Answer: All of these I’m pretty sure

Explanation: It just makes sense
8 0
2 years ago
Compute the reactance of a 0.450 H inductor at the frequency of 60.0 Hz. Express your answer in ohms.
vlada-n [284]

Answer:

169.67Ω

Explanation:

This question is asking for the inductive reactance, which is calculated as follows:

X(L) = 2πfL

Where;

X(L) = inductive reactance (Ω)

f = frequency (Hz)

π = 3.142

L = inductance (Henry)

Given the information provided, f = 60Hz, L = 0.450H

X(L) = 2πfL

X(L) = 2 × 3.142 × 60 × 0.450

X(L) = 6.284 × 60 × 0.450

X(L) = 6.284 × 27

X(L) = 169.668

X(L) = 169.67Ω

7 0
3 years ago
A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo
dimaraw [331]

<u>Answer:</u> The value of K_c for given reaction is 0.465

<u>Explanation:</u>

We are given:

Initial concentration of A = 0.650 M

Initial concentration of B = 1.35 M

Initial concentration of C = 0.300 M

Equilibrium concentration of A = 0.550 M

Equilibrium concentration of B = 0.400 M

For the given chemical equation:

                           A+2B\rightarrow C

<u>Initial:</u>                0.65     1.35     0.30

<u>At eqllm:</u>        0.65-x   1.35-2x   0.30+x

Evaluating the value of 'x'

0.650-x=0.550\\\\x=0.100

So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M

Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M

The expression of K_c for above equation follows:

K_c=\frac{[C]}{[A][B]^2}

Putting values in above equation, we get:

K_c=\frac{0.400}{0.650\times (1.15)^2}\\\\K_c=0.465

Hence, the value of K_c for given reaction is 0.465

7 0
3 years ago
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