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nekit [7.7K]
4 years ago
13

Find the sum of the given polynomials.

Mathematics
2 answers:
enot [183]4 years ago
8 0
Number 4 is your answer
DanielleElmas [232]4 years ago
6 0

Answer:

the real answer is 10x^2 + 2x − 9

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Shade in circles and write equivalent fractions 3/6​
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HELP! Multiplying radicals. Questions on photo.
DerKrebs [107]
These are 10 questions and 10 answers

1) \sqrt[3]{24}  . \sqrt[3]{45}


Answer: third option 6∛5

Explanation:

24 = 2^3 * 3

45 = 3^2 * 5

=> 24 * 45 = 2^3 * 3^3 * 5

=> (∛24).(∛45) = ∛[ (2^3).(3^3).5 ] = (2)(3)∛5 = 6∛5

2) \sqrt[5]{4x^2} . \sqrt[5]{4x^2}

Answer: second option.

Demostration:

 \sqrt[5]{4x^2} . \sqrt[5]{4x^2} =  \sqrt[5]{4^2x^4} = \sqrt[5]{2^4x^4} = \sqrt[5]{16x^2}

3) \sqrt{10} . \sqrt{10}

Answer: first option 10

Justification:

√10 . √10 = (√10)^2 = √(10^2) = √100 = 10

4) \sqrt[4]{7} . \sqrt[4]{7} . \sqrt[4]{7} . \sqrt[4]{7}

Answer: fourth option: 7

Explanation:

\sqrt[4]{7} . \sqrt[4]{7} . \sqrt[4]{7} . \sqrt[4]{7}= (\sqrt[4]{7^})^4= \sqrt[4]{7^4}=7 ^{4/4}=7^1=7

5) (x \sqrt{7} -3 \sqrt{8}).(x \sqrt{7}-3 \sqrt{8})

Answer: the third option: 7x^2 - 12x√14 + 72

Solution:

Notice that it is the two factors are identical, so this is a perfect square binomial:

(x√7 - 3√8)^2 = (x√7)^2 - 2*(x√7)(3√8) + (3√8)^2 = 7x^2 - 6√(56)x + 72 =

= 7x^2 -(6)(2)x√14 + 72 = 7x^2 - 12x√14 + 72

6) √12 . √18

Answer: the fourth option 6√6

Explanation:

√12 . √18 = √ (2 . 2 . 3 . 2 . 3 . 3) = √ [( 2^3) . (3^3)] = 2 . 3 √6 = 6√6

7) \sqrt{y^3} . \sqrt{y^3}

Answer: first option y^3

Justification:

\sqrt{y^3} . \sqrt{y^3} =( \sqrt{y^3} )^2 =(y^3)^{2/2}=y^3

8) ∛d . ∛d . ∛d

Answer: first option: d

Explanation:

∛d . ∛d . ∛d =     ( \sqrt[3]{d}) ^3 = d{3/3}=d^1=d

9) \sqrt{5x^8y^2} . \sqrt{10x^3} . \sqrt{12y}

Answer: second option

Explanation:

\sqrt{5x^8y^2} . \sqrt{10x^3} . \sqrt{12y} = \sqrt{(5.10.12)x^8y^2x^3y}= \sqrt{600x^{11}y^3} =

=10x^5y \sqrt{6xy}

10) (∛4) . √3

Answer: third option     \sqrt[6]{432}

Explanation:

\sqrt[3]{4} . \sqrt{3} = \sqrt[6]{4^2} . \sqrt[6]{3^3} = \sqrt[6]{16.27} = \sqrt[6]{432}
5 0
3 years ago
What’s the ratios of each
bagirrra123 [75]

<u>Given</u>:

The triangle ABC is a right triangle.

The length of AC = 25, the length of AB = 7 and the length of BC = 24

We need to determine the ratios of sin C, cos C and tan C.

<u>Ratio of sin C:</u>

Using the trigonometric ratio, the ratio of sin C is given by

sin \ C=\frac{opp}{hyp}

where opp=AB and hyp=AC

Thus, we get;

sin \ C=\frac{AB}{AC}

Substituting the values, we get;

sin \ C=\frac{7}{25}

Thus, the ratio of sin C is \frac{7}{25}

<u>Ratio of cos C:</u>

The ratio of cos C can be determined using the trigonometric ratio.

Thus, we have;

cos C=\frac{adj}{hyp}

where adj=BC and hyp=AC

cos \ C=\frac{BC}{AC}

Substituting the values, we get;

cos \ C=\frac{24}{25}

Thus, the ratio of cos C is \frac{24}{25}

<u>Ratio of tan C:</u>

The ratio of tan C can be determined using the trigonometric ratio.

Thus, we have;

tan \ C=\frac{opp}{adj}

where opp=AB and adj=BC

Thus, we have;

tan \ C=\frac{AB}{BC}

Substituting the values, we get;

tan \ C=\frac{7}{25}

Thus, the ratio of tan C is \frac{7}{25}

3 0
3 years ago
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