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3 years ago

Find the sum of the given polynomials.

Mathematics

2 answers:

enot [183]3 years ago

8 0

Number 4 is your answer

DanielleElmas [232]3 years ago

6 0

Answer:

the real answer is 10x^2 + 2x − 9

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Write an equivalent expression by factoring.<br><br>5x + 15

nata0808 [166]

Answer:

5(x+3)........ ...........

5 0

3 years ago

The number of carbon atoms in a fossil is given by the function y= 5100(0.95)^x where x represents the number of years since bei

natita [175]

Answer:

This is a guess!

When looking at the given equation I can not help but think of compound interest. So I am going to convert this into that format.

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Within the context of financial interest:

Looking for:

(

−

)

Where P is the principle sum,

is the interest and n is the number of interest cycles (annual)

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Given:

5100

(

0.95

)

But

0.95

−

0.05

so we have

5100

(

−

0.05

)

But

0.05

100

So we have

5100

(

−

100

)

Thus the percentage change each year is

−

Step-by-step explanation:

8 0

3 years ago

What’s the distance for someone that drove 60 miles for 12 hours

Colt1911 [192]

Answer:

720 miles.

Step-by-step explanation:

Going 60 miles per hour for 12 hours would amount to driving 720 miles in total.

3 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$