Multiply each term by a^2b^2:-
b^2y^2 + a^2x^2 = a^2b^2
subtract a^2x^2 from both sides
b^2y^2 = a^2b^2 - a^2x^2
Now divide both sides by b^2
y^2 = a^2 - a^2x^2 / b^2 = a^2 (1 - x^2/b^2)
take positive square root ( because y > 0)
y = a sqrt(1 - x^2/b^2)
I think it’s c I’m not to sure thi
Answer:
m = - 8 ± 6
Step-by-step explanation:
Given
m² + 16m - 8 = 0 ( add 8 to both sides )
m² + 16m = 8
To complete the square
add ( half the coefficient of the m- term )² to both sides
m² + 2(8)m + 64 = 8 + 64
(m + 8)² = 72 ( take the square root of both sides )
m + 8 = ±
= ±
= ± 6
Subtract 8 from both sides
m = - 8 ± 6
N^2 should be the correct answer. Based on those numbers, it appears that the sum can be found by squaring the term n
Not as hard as you think.
Just multiply all the prime factors together.