Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
In 8rows and 3 in each so 8 times 3 is 24
<span>0.04 inches squared - because it's 0.2 inches squared.
<span><span><span><span>
This can also be written as 1/25 inches squared</span></span></span></span></span>
Answer:
(155.301 ; 159.299)
Step-by-step explanation:
Xbar = 157.3
Sample size, n = 234
Population standard deviation, σ = 15.6
The confidence interval :
Xbar ± standard Error
Standard Error = Zcritical * σ/√n
Zcritical at 95% = 1.96
Standard Error = 1.96 * (15.6/√234) = 1.999
Lower boundary : 157.3 - 1.999 = 155.301
Upper boundary : 157.3 + 1.999 = 159.299
(155.301 ; 159.299)
