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Artyom0805 [142]
3 years ago
7

HELP ME! idk how to do this.

Mathematics
2 answers:
miss Akunina [59]3 years ago
5 0
Lol the doodles. your a good artist. as for the question pat is incorrect about the parallelograms not being the same. she made her assumption based on the angle of the shape rather than calculating the area of both shapes.
jasenka [17]3 years ago
3 0
The first one: The formula for a trapezoid is 1/2 h(b1+ b2) or if you split it up do 1/2 the base times the height on the triangle, then do length times width on the rectangle.
The second one: Just put and imaginary line down the sides of the H leaving the middle. The dimensions of the middle are, 3 by 4. The dimensions of the two sides are 12 by 3. Just multiply length times width, and for the two long sides... multiply by two. You should get 72 for it. Just add twelve to that, and you are good to go!
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Deborah spent $70 on food and clothes. She spent $26 more on clothes than on food. On your worksheet, solve the question and wri
dolphi86 [110]

Answer:

food : 22

clothes : 48

Step-by-step explanation:

70 - 26 = 44

44 divided by 2 = 22

22 + 26 = 48

70 - 48 = 22

7 0
2 years ago
If EF bisects CD, CG =5x-1, GD = 7x-13, EF = 6x-4, and GF =13, find EG
VARVARA [1.3K]

<em>Greetings from Brasil....</em>

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13      x = 6, so

6·6 - 4 = EG + 13

<h2>EG = 19</h2>

<em>(see attachment)</em>

6 0
3 years ago
If you reflect (–2, –8) across both axes, which quadrant will it be in? Justify your reasoning.
stepan [7]
The quadrant would be the first one, because once reflected over the y-axis, it would become (2,-8), and once reflected over the x-axis, it would become (2,8)
8 0
3 years ago
Read 2 more answers
If I have 147 cups for a party and don’t have enough and Sarah gives me 154 how many do I have?
DENIUS [597]
147 + 154 = 301 cups.
3 0
3 years ago
Read 2 more answers
What is the point slope equation of a line with slope -5 that contains the point (6,3)
ehidna [41]

Step-by-step explanation:

Given

Slope (m) = -5

Point

(x1 , y1) = ( 6 , 3)

So the equation is

y - y1 = m ( x - x1)

y - 3 = -5 ( x - 6)

y - 3 = -5x +30

5x + y = 30 + 3

5x + y = 33

5x + y - 33= 0

Which is the required equation.

Hope it will help you :)

3 0
3 years ago
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